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2 years ago

Mr. Goodman is unresponsive. Valerie must now simultaneously check for breathing and a pulse for no more than ___.

1 answer:

7 0

Since Goodman is unresponsive, Valerie shall check for breathing and a pulse simultaneously for no more than <u>10 seconds</u>.

<h3>What is cardiac cycle?</h3>

Cardiac cycle is a process that involves the complete heartbeat of the human heart, which comprises sequential alternating contraction and relaxation of the atria and ventricles, so as to cause blood to only flow in one direction throughout the human body and aid respiration (breathing).

As a general rule, Valerie shall check for breathing and a pulse simultaneously for for at least 5 seconds, but shouldn't be more than <u>10 seconds</u>.

Read more on pulse here: brainly.com/question/14528211

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The nurse assesses a postpartum woman's perineum and notices that her lochial discharge is moderate in amount and red. The nurse

Zarrin [17]

The type of lochia that the nurse would record the moderate discharge from the lochial is Lochia Rubra.

<h3>What is a lochia Rubra?</h3>

This is one of the stages in the condition known as lochia. It is considered the first stage and doesn't come with too heavy a flow.

Instead, the flow will be moderate and red and will eventually become light after about 4 days.

Find out more on lochia rubra at brainly.com/question/15835433

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7 0

2 years ago

Factor the expression into an equivalent form 12y^2-75.

elena-14-01-66 [18.8K]

Hello oddworld7836!

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

Factor the expression into an equivalent form 12y² - 75.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$12 y ^ { 2 } - 75$

By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.

$12 y ^ { 2 } - 75 \\ = 3\left(4y^{2}-25\right)$

Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,

a² = 4, a = 2 (√a² = ✓4 = 2)
b² = 25, b = 5 (√b² = ✓25 = 5)

So, the (4y² + 25) becomes...

$(4 {y}^{2} - 25) \\ = \left(2y-5\right)\left(2y+5\right)$

Now, bring the 3 (common factor) & rewrite the complete expression.

$12 y ^ { 2 } - 75 \\ = \boxed{ \boxed{ \bf \: 3\left(2y-5\right)\left(2y+5\right) }}$

We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.

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Hope it'll help you!

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8 0

2 years ago

In a closed system a reversible chemical reaction will reach a state of dynamic chemical when the rate of the forward reaction i

vitfil [10]

In a closed system a reversible chemical reaction will reach a state of dynamic chemical equilibrium when the rate of the forward reaction is to be in or equal to the rate of the reverse reaction.

<h3>What occurs if a reaction reaches dynamic equilibrium in a closed system?</h3>

A closed chemical system is said to attain dynamic equilibrium if the rate of the forward reaction is said to have equals the rate of the backward reaction and also the level of concentrations of products and reactants are said to be the same.

Hence, In a closed system a reversible chemical reaction will reach a state of dynamic chemical equilibrium when the rate of the forward reaction is to be in or equal to the rate of the reverse reaction.

Learn more about reverse reaction from

brainly.com/question/16614855

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6 0

2 years ago

A child riding a bicycle at 15 m/s accelerates at 3. 0 m/s/s for 4. 0 s. What is the child's speed at the end of this 4. 0 s int

mamaluj [8]

Answer:

The final speed of bicycle would be <u>27 m/s</u>².

Step-by-step explanation:

<u>Given</u> :