Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
Answer: 7/6 or 1 and 1/6
Step-by-step explanation:
2 1
+
3 2
you have to make them have the same denominators(the number on the bottom of a fraction)
2/3--> 4/6
1/2---> 3/6
4/6+3/6=7/6 or 1 and 1/6
Answer:
a)10
b)-11.4
Step-by-step explanation:
you should find common denominator bit don't forget that they are negative
The first one is correct but I don’t know about the second one
