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Phoenix [80]
1 year ago
13

3. Today, Dahlia folded 29 paper cranes. Now there are 41 paper cranes in class. How many cranes were there in class yesterday?

Each paper crane has a length of 10 centimetres. How many centimetres were there total for all the paper cranes?​
Mathematics
1 answer:
ohaa [14]1 year ago
4 0

Answer:

There were 12 cranes in class yesterday. For all the cranes, there were a total of 290 centimeters.

Step-by-step explanation:

41-29=12.

29*10=290

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Answer is 6 you have to use distributive property to combine terms and than you simplify to get the answer<span />
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2 years ago
Find the side length of triangle.
Llana [10]

Answer:

x=4

Step-by-step explanation:

Let's solve the equation:

3x+12=4x+8

12=4x-3x+8

12=x+8

12-8=x

4=x

x=4

The way i got this answer was by solving the equation using the following steps. Since you're solving for one side and have two different equations, put an equal sign in between the two equations to get the equation set up above. Then you need to have the x variable on one side, instead of both sides, so you take 3x and subtract it from both sides, leaving x on one side, because 4x-3x is equal to 1x, or just x. Then we need to have what is not attached to a variable on the other side to make it easier to solve, so you would need to subtract 8 from both sides to get rid of the 8 on the side with the variable, because if you subtract 12 from both sides, it will just make it more confusing to solve, and then 12-8 is equal to 4, so you get x is equal to 4.

3 0
3 years ago
Question 6 Multiple Choice Worth 1 points)
OleMash [197]

Answer:

Quantity A because it changes with gravitational pull.

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That is why an astronaut weighs about three times more on earth than on Mars. The gravitational acceleration on Mars is about one third that on earth.

5 0
2 years ago
For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
2 years ago
Help with #7 please I don’t understand
quester [9]

Answer:

A

Step-by-step explanation:

(2x^2 + 3x - 4) (x + 4)


FOIL.


2x^2 times x = 2x^3

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2x^2 times 4 = 8x^2

3x times 4 = 12 x

-4 times 4 = -16


Combine like terms to get 2x^3 + 11x^2 + 8x - 16.

4 0
2 years ago
Read 2 more answers
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