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STALIN [3.7K]
3 years ago
13

the shaded area of the following shape can be found by subtracting the area of the circle from the area of the triangle?

Mathematics
1 answer:
balu736 [363]3 years ago
7 0
I found the accompanying picture of this word problem.

The circle was inscribe in the triangle. The area outside of the circle but inside the triangle is the shaded area.

True. The shaded area of the following shape can be found by subtracting the area of the circle from the area of the triangle.
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For brainiest:):):):):):):)
andrew-mc [135]

Answer:

15 = 0.025

16= 3 years

Step-by-step explanation:

15.

I=prt

15= (200)(r)(3)

200(3) = 600r

15 divided by 600r = 40 (0.025)

------------------------------------------------------

16.

I=prt

t= \frac{I}{Ixp} \\t= \frac{90}{0.05x600} \\t= 3

t= 3 years

5 0
3 years ago
One number is 8 greater than another. The product of the numbers is 84. Find the numbers.
mario62 [17]

Let x,y be the two numbers.

Given that one number is 8 greater than another.

Let x be the smaller number ans y be the greater number.

That is y=x+8. Let this be the first equation.

And also given that product of the two numbers is 84.

That is x × y = 84, let us plugin y=x+8 here.

x × (x+8) = 84

x²+ 8x -84 = 0.

x²+12x-4x-84 = 0

x(x+12)-4(x+12) =0

(x-4)(x+12)=0

That is x= 4 or -12.

<h3>If x=4 , y= 4+ 8 = 12</h3>

<h3>If x= -12, y= -12+8 = -4 </h3>

Hence two positive numbers corresponding to given conditions are 4,12.

And two negative numbers corresponding to given conditions are -12,-4.

Step-by-step explanation:

hope it may help you!!

please mark as brainlist please (´;︵;`)

5 0
3 years ago
Help plz I really need the help​
Colt1911 [192]

Answer:

the answer might be either one of the four

3 0
3 years ago
Can somebody help me with this question please ?
inysia [295]

Answer: No.

Step-by-step explanation: g should also be factored out. 10g(a - 3z).

4 0
2 years ago
Can someone help me solve #9!?
yarga [219]
Dy/dx = (4y²)(x⁴/³)

Find ∫(4y²)(x⁴/³) =∫(4y²∛(x⁴)dx = 3∛(x⁴).y² +c or 3x⁴/³.y² + c
4 0
3 years ago
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