Answer:
maths question
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Answer:5,4 and 2
Step-by-step explanation:
i just answered this question its right
Answer:
The chances of Yvonne to get a blue berry candy in the two cases are 1 and 1/2 in case 1 and 2/3 in the case 2.
Step-by-step explanation:
Maurice has a paper bag with three hard candies
2 blueberries and 1 green apple
Yvonne and Kate want 1 candy each
It is not mentioned that ether Kate has taken a candy already before Yvonne or not so we will consider both the cases
Case 1
If Kate has picked a candy before Yvonne
- If Kate gets an Apple green candy then the probability or Yvonne to get a Blueberry will be = 2/2 = 1 ( as there will 2 blueberry candy left in the bag)
- If Kate has taken a Blueberry candy then there will be 1 blueberry and 1 apple green candy in the bag so the probability of Yvonne to get a Blueberry candy will be = 1/2
Case 2
If Kate has not taken any candy from the bag before Yvonne
Probability that Yvonne will get a blueberry candy will be = 2/3
Therefore the chances of Yvonne to get a blue berry candy in the two cases are 1 and 1/2 in case 1 and 2/3 in the case 2.
x/3-4 =10
add 4 to each side:
x/3 =14
multiply both sides by 3:
x = 42
W = 2L - 3
43 = L × ( 2L - 3 )
43 = 2L^2 - 3L
2L^2 - 3L - 43 = 0
L = 5.447 , L = - 3.9471
w = 2(5.447) - 3
w = 7.894
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