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o-na [289]
3 years ago
7

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.

Mathematics
1 answer:
marishachu [46]3 years ago
6 0

Answer:

\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18

Step-by-step explanation:

We have been given the function

f(x)=-2x^2+4x^3+3x^2+18

From the rational zeros theorem, we have

\text{Possible rational zeros}=\pm\frac{\text{Factors of constant term}}{\text{Factors of leading coefficient}}

From the given function,

Leading coefficient = 2

Factors of 2 are 1,2

Constant term = 18

Factors of constant term = 1, 2, 3, 6, 9, 18

Hence, we have

\text{Possible rational zeros}=\pm\frac{1,2,3,6,9,18}{1,2}\\\\\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18

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ladessa [460]

Answer:

(-2, 4, -2)

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Step-by-step explanation:

So we have the three equations:

4x-y-2z=-8\\-2x+4z=-4\\x+2y=6

And we want to find the value of each variable.

To solve this system, first look at it and consider what you should try to do.

So we can see that the second and third equations both have an x.

Therefore, we can isolate the variables for the second and third equation and then substitute them into the first equation to make the first equation all xs.

Therefore, let's first isolate the variable in the second and third equation.

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First, divide everything by -2 to simplify things:

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(x-2z)-x=2-x\\-2z=2-x

Now, divide everything by -2 to isolate the z:

z=-\frac{2-x}{2}

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x+2y=6

Subtract x from both sides:

2y=6-x

Divide both sides by 2:

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Now that we've isolated the y and z variables, plug them back into the first equation. Therefore:

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Combine like terms:

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Now, plug this back into the second and third simplified equations to get the other values.

Second equation:

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Third equation:

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Therefore, the solution is (-2, 4, -2)

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