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Neko [114]
2 years ago
5

PLEASE ANSWERERRREEERRR

Mathematics
1 answer:
Vladimir79 [104]2 years ago
5 0

the operation:

2*10^1 - 4*10^0 = 20 - 4 = 16

Gives a square number.

<h3>How to get a perfect square?</h3>

A perfect square is the product of a number and itself.

As you can see in the example, 16 is a square number. Then let's try to get 16.

To get 16 we can use the difference:

20 - 4

So the first therm needs to be equal to 20, and the second equal to 4.

To write 20 in scientific notation we have:

2*10^1

To write 4 in in scientific notation:

4*10^0

Then the operation:

2*10^1 - 4*10^0 = 20 - 4 = 16

Gives a square number.

If you want to learn more about square numbers:

brainly.com/question/21694652

#SPJ1

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a town has a population of 14000 and grows at 4.5% each year. to the nearest tenth of a year how long will it be until the popul
denis-greek [22]

Answer:

about 6.6 years

Step-by-step explanation:

41,500=14,000*.45*x

41,500=6,300*x

41,000/6,300=x

6.5873=x

6.6=x

6 0
3 years ago
How do you simplify this
Dafna11 [192]

Top:

x / (x + 1) - 1 / x

= [x^2 - (x +1)] / x(x+1)

= (x^2 - x - 1 ) / x (x+1)

Bottom:

x / (x + 1) + 1 / x

= [x^2 + (x +1)] / x(x+1)

= (x^2 + x + 1 ) / x (x+1)

Now you have:

(x^2 - x - 1 ) / x (x+1)

----------------------------

(x^2 + x + 1 ) / x (x+1)

= (x^2 - x - 1 ) / x (x+1) * x (x+1) / (x^2 + x + 1 )

= (x^2 - x - 1 ) /(x^2 + x + 1 )

Answer:

x^2 - x - 1

---------------------

x^2 + x + 1

7 0
3 years ago
David’s statement shows a previous balance of $5834.53, a payment of $150, and new transactions totaling $325. His APR is 20.4%.
DaniilM [7]
Finance charge
(5,834.53−150)×(0.204÷12)=96.64

New balance
5,834.53−150+96.64+325
=6,106.17
8 0
3 years ago
Read 2 more answers
If sine of the quantity x plus y end quantity equals one half times sine of x plus radical 3 over 2 times cosine of x. What is t
miskamm [114]

The value of y from the given trig expression is pi/3 rad

<h3>Trigonometry identity</h3>

These identities are expressed in terms of sine, cosine and tangent

Given the expression

sin(x+y)=\frac{1}{2}sinx+\frac{\sqrt{3}}{2} cosx


Expand sin(x+y)

sin(x+y) = sinxcosy + cosxsiny

Compare both equations

cosy = 1/2

y = arccos(1/2)

y = 60 degrees

y = pi/3 rad

Hence the value of y from the given trig expression is pi/3 rad

Learn more on trig function here: brainly.com/question/24349828

#SPJ1

8 0
2 years ago
A pumpkin is thrown horizontally off of a building at a speed of 2.5\,\dfrac{\text m}{\text s}2.5 s m ​ 2, point, 5, start fract
4vir4ik [10]

Answer:−47.0

​

​

Step-by-step explanation:Step 1. List horizontal (xxx) and vertical (yyy) variables

xxx-direction yyy-direction

t=\text?t=?t, equals, start text, question mark, end text t=\text?t=?t, equals, start text, question mark, end text

a_x=0a

x

​

=0a, start subscript, x, end subscript, equals, 0 a_y=-9.8\,\dfrac{\text m}{\text s^2}a

y

​

=−9.8

s

2

m

​

a, start subscript, y, end subscript, equals, minus, 9, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction

\Delta x=12\,\text mΔx=12mdelta, x, equals, 12, start text, m, end text \Delta y=\text ?Δy=?delta, y, equals, start text, question mark, end text

v_x=v_{0x}v

x

​

=v

0x

​

v, start subscript, x, end subscript, equals, v, start subscript, 0, x, end subscript v_y=\text ?v

y

​

=?v, start subscript, y, end subscript, equals, start text, question mark, end text

v_{0x}=2.5\,\dfrac{\text m}{\text s}v

0x

​

=2.5

s

m

​

v, start subscript, 0, x, end subscript, equals, 2, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction v_{0y}=0v

0y

​

=0v, start subscript, 0, y, end subscript, equals, 0

Note that there is no horizontal acceleration, and the time is the same for the xxx- and yyy-directions.

Also, the pumpkin has no initial vertical velocity.

Our yyy-direction variable list has too many unknowns to solve for v_yv

y

​

v, start subscript, y, end subscript directly. Since both the yyy and xxx directions have the same time ttt and horizontal acceleration is zero, we can solve for ttt from the xxx-direction motion by using equation:

\Delta x=v_xtΔx=v

x

​

tdelta, x, equals, v, start subscript, x, end subscript, t

Once we know ttt, we can solve for v_yv

y

​

v, start subscript, y, end subscript using the kinematic equation that does not include the unknown variable \Delta yΔydelta, y:

v_y=v_{0y}+a_ytv

y

​

=v

0y

​

+a

y

​

tv, start subscript, y, end subscript, equals, v, start subscript, 0, y, end subscript, plus, a, start subscript, y, end subscript, t

Hint #22 / 4

Step 2. Find ttt from horizontal variables

\begin{aligned}\Delta x&=v_{0x}t \\\\ t&=\dfrac{\Delta x}{v_{0x}} \\\\ &=\dfrac{12\,\text m}{2.5\,\dfrac{\text m}{\text s}} \\\\ &=4.8\,\text s \end{aligned}

Δx

t

​

 

=v

0x

​

t

=

v

0x

​

Δx

​

=

2.5

s

m

​

12m

​

=4.8s

​

Hint #33 / 4

Step 3. Find v_yv

y

​

v, start subscript, y, end subscript using ttt

Using ttt to solve for v_yv

y

​

v, start subscript, y, end subscript gives:

\begin{aligned}v_y&=v_{0y}+a_yt \\\\ &=\cancel{0\,\dfrac{\text m}{\text s}}+\left(-9.8\,\dfrac{\text m}{\text s}\right)(4.8\,\text s) \\\\ &=-47.0\,\dfrac{\text m}{\text s} \end{aligned}

v

y

​

​

 

=v

0y

​

+a

y

​

t

=

0

s

m

​

​

+(−9.8

s

m​

)(4.8s)

=−47.0

s

m

5 0
3 years ago
Read 2 more answers
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