Write the equation of a line in standard form that passes through (-2, 5) and is perpendicular to
1 answer:
Answer:
Step-by-step explanation:
x - 2y = 8
Write this in y = mx +b form
- 2y = -x + 8
Divide the equation by (-2)
Slope = 1/2
The slope of the perpendicular line = -1/m
m = -2 , ( -2 , 5)
Equation: y = mx +b
Plug in m = -2 ,x = -2 and y =5
5 = (-2)*(-2) + b
5 = 4 + b
5 - 4 = b
b = 1
Equation of the line:
y = mx +b
y = -2x + 1
You might be interested in
In trigonometry, we start from the point (1,0), so this is the 0-degree point. Then, we start rotating counter clockwise along the unit circle.
Note that rotating 180 or -180 degrees is actually the same, because you travel half the circumference clockwise or counter clockwise. In both cases, you start from the rightmost point of the circle, (1,0), and arrive at the leftmost point, (-1,0).
Now, for every point (x,y) on the unit circle, given by a certain angle , we have
So, in this case, the angle of -180 is associated with the point (-1,0), and thus we have