Answer:
260,548668 or 260.55 round to the nearest hundreds
Step-by-step explanation:
Area of the trapezoid:
[(major base + minor base)x height]/2
[(22 + 12) x 12]/2 = 204 cm^2
radius = diameter / 2 = 12 / 2 = 6 cm
Area of a semicircle
(radius^2 x pi)/2 = (6^2 x pi)/2 = 56.548668 cm^2
total area = 204 + 56,548668 = 260,548668 cm^2
Answer:
The correct answer is 24
Step-by-step explanation:
to solve this you will need to use the pathagreom theorum
a^{2}+b^{2}=c^{2}
A= one side lenth
B= the secons side lenth
C= hypotnuse
It is helpfull to draw out the situation
you know that the latter is 25 ft, that is your hypotnuse
you also know that the 7 ft away from the base of the building is one of the side lenths, lets call it side a
so plug the numbers into the equation
7^2 + b^2 = 25 ^2
you leave b^2 alone because that is the side you are trying to find
now square 7 and 25 but leave b^2 alone
49 + b^2 = 625
now subtract 49 from both sides
b^2 = 576
now to get rid of the square of b you have to do the opposite and square root both sides removing the square of the B and giving you the answer of..........
B= 24
Hope this helped!! I tryed to explain it as simpil as possiable
The coefficient of b is h/2. Multiply the equation by the reciprocal of that.
(2/h)A = (2/h)·(h/2)·b
b = 2A/h . . . . . simplify
