I will create a set of arbitrary constants (x1,y1) (x2,y2)
slope = y2-y1/x2-x1
y = (y2-y1/x2-x1)x + b
y2 = (y2-y1/x2-x1)x2 + b
b = y2 - (y2-y1/x2-x1)x2
y = (y2-y1/x2-x1)x + [y2 - (y2-y1/x2-x1)]
Choose any points and just
Plug the values and you have a linear function.
NOT SURE IF THAT'S WHAT THE QUESTION WANTS.
| 1 2 ||x| = |4| - | 3 -1 ||y| |6| <span>-3 | 1 2||x| = |4| </span>
<span>| 3 -1||y| |6| </span>
<span>|-3 -6||x| = |-12| </span>
<span>| 3 -1||y| |6 | </span>
<span>| 0 -7 ||x| = | -6 | </span>
<span>| 3 -1 ||y| | 6 | </span>
<span>y = 6/7 </span>
<span>x = 16/7</span>
(x + 2) = 3
-2 -2
0 1
x = 1
Answer:
254.34 ft^2
Step-by-step explanation:
A=1/4(3.14)d^2= 1/4(3.14)(8)^2= 254.34 ft^2
Answer:
Hmmm What about the pair of skew lines lol
Step-by-step explanation:
Could you add more details/options !!!!
-I'd be glad to help <3 !!!!
