Question

Find the term that must be added to the equation x2 6x=1 to make it into a perfect square.

Answer 1

The value added to the equation $x^2-6x=1$ exists $x^2-6x+9=10$.

What is a perfect square?

A perfect square exists as a number that can be described as the product of an integer by itself or as the second exponent of an integer.

The perfect square trinomial exists

$(a$ ± $b)^2$ = $a ^2$ ± 2ab + $b ^2$

$x^2-6x=1$

$x^2-2*3x=1$

then $2ab = 2 * 3*x = 2 * x *3$

The value of a = x and b = 3

$b^2=3^2=9$

$x^2-6x+9=1+9$

$x^2-6x+9=10$

The value added to the equation $x^2-6x=1$ exists $x^2-6x+9=10$.

To learn more about perfect square refer to: brainly.com/question/6946048

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