A line segment that goes from one side of the circle to the other side of the circle and doesn't go through the center is:

1 answer:

7 0

A line segment that goes from one side of the circle to the other side of the circle and doesn't go through the center is called chord of circle.

Since,

The chord of a circle can be defined as the line segment joining any two points on the circumference of the circle.

The diameter is the length of the line through the center that touches two points on the edge of the circle.

So, we can say that every diameter of a circle is always called chord (longest chord) but every chord of the circle is not a diameter because the diameter passes to the circle's center but it not necessay that evey chord will pass through the center of the circle. Some, line segment goes from one side of the circle to the other side and doesn't pass through centre then for this case the line segment is called chord of the circle.

Hence, a line segment that goes from one side of the circle to the other side of the circle and doesn't go through the center is called chord of the circle.

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A quadratic function is one that can be written as an equation of the form:

f (x) = ax² + bx + c

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In this case, f(x) is P(c) [the power generated], x is the current c (in amperes), a = -12, b = 120 and c = 0.

The vertex is a point that is part of the parabola, which has the value as ordered minimum or maximum function. If the scalar a> 0, the parabola opens or faces up and the vertex is the minimum of the function. In contrast, if a <0, the parabola opens downward and the vertex is the maximum of the function.

The calculation of the vertex, which in this case will be the maximum of the function, is carried out as follows:

The value of x, in this case the value of current c in amperes, can be calculated with the formula $c=\frac{-b}{2*a}$ . In this case: $c=\frac{-120}{2*(-12)}$ So c= 5 amperes. The current is 5 amperes.
The value of y, in this case the value of the electric current in watts, is obtained by substituting the value of c previously obtained in the function. In this case: P(5)= -12*5²+120*5. So P(5)= 300 watts