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Harman [31]
2 years ago
14

How long was Anthony's family gone? Complete the explanation of how the answer can be found. To find the answer, count hour(s) f

rom 5:05 to 6:05. Then count minutes to 6:35. Then count minutes to 6:45 and minutes to 6:51. I add them all up to get that the Anthony's family was gone hour(s) and minutes. Anthony's family went out to dinner. They left at the time shown on the clock. They returned home at 6:51 P.M.
Mathematics
1 answer:
creativ13 [48]2 years ago
8 0

Answer:

Thus, the Anthony's family were away for  1 hour 46 minutes

Step-by-step explanation:

We are being told  that Anthony's family went out to dinner and they left at the time shown on the clock (i.e 5;05 P.M) and they returned home at 6:51 P.M.

We are to calculate how long was Anthony's family gone

We all know that:

60 seconds = 1 minute

60 minutes = 1 hour

So from  5:05 to 6:05 = 60 minutes

From 6:05 to 6:35 = 30 minutes

From 6:35 to 6:45 = 10 minutes

From 6:45 to 6:51 = 6 minutes

Therefore ; to deduce how long was Anthony's family gone; we will have to sum up the values of the minutes from the above time- frames up;

So;  (60  + 30  + 10  + 6 ) minutes

= 106 minutes

since 60 minutes = 1 hour

Then 106 minutes = 1 hour 46 minutes

Thus, the Anthony's family were away for  1 hour 46 minutes

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Answer:

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Step-by-step explanation:

8 0
3 years ago
Gerry ran 3/8 of a mile on Monday. He ran 5/8 of a mile on tuesday he ran 1/2 mile on Wednesday how many miles in all did Gerry
pickupchik [31]
1 and 1/2 miles in total
3 0
2 years ago
Read 2 more answers
50 POINTS! :D
Alexxandr [17]

Answer:

The speed of the first car is 60 mph

Step-by-step explanation:

speed = distance/time

Solve the above equation for distance to get

distance = speed * time

or simply

d = st

Now we use this formula for distance to write an equation for each car.

Let s = speed of second car

Then since the speed of the first car is 10 mph faster, the first car's speed is s + 10.

The time the two cars traveled is equal but unknown, so let the time = t.

First car: speed = s + 10; time = t; distance = 120 miles

d = st

120 = (s + 10)t    

(s + 10)t = 120      Equation 1

Second car: speed = s; time = t; 100 miles

d = st

100 = st

st = 100       Equation 2

Equations 1 and 2 form a system of 2 equations in 2 unknowns.

(s + 10)t = 120

st = 100

Distribute t in the first equation.

st + 10t = 120

From the second equation we know st = 100, so substitute 100 for st.

100 + 10t = 120

10t = 120

t = 2

The time traveled was 2 hours.

Equation 2:

st = 100

Substitute t with 2.

s * 2 = 100

s = 50

The speed of the second car was 50 mph.

The speed of the first car is s + 10.

s + 10 = 50 + 10 = 60

Answer: The speed of the first car is 60 mph

8 0
3 years ago
Help. after i post this i will have 2 points lwft
Thepotemich [5.8K]

The slope is the ratio between the change in the y and x values. When you write a line as y=mx+q, the slope is the coefficient m. So, the slope of the first graph is 405, which means that the first plane flies with a speed of 405 miles per hour.

Similarly, from the table we can see that each time you increase x by 1, the distance traveled increases by 435. So, the slope of the second graph is 435, which means that the second plane flies with a speed of 435 miles per hour, and is thus faster.

4 0
3 years ago
7 and 1/4 divided by 5/6 as a fraction or mixed number in simplest form
Alchen [17]
First off, turn 7 1/4 into a mixed number, 29/4. change 29/4  /  5/6   into a multiplication question by flipping 5/6 into 6/5 (AKA multiplying by the reciprocal) so you get 29/4  X  6/5. then multiply so you get 174/20. Next, simplify into a mixed number by seeing how many times 20 goes into 174, and then putting the leftovers into a fraction, so you get 8 14/20, then simplify even further so you get 8 7/10. 
3 0
2 years ago
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