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3 years ago

By what factor must you multiply a number in order to triple its square root?

1 answer:

4 0

To solve the problem shown above you must apply the following proccedure:

1. Let's call:

x: a number.
f: the factor.

2. Then, you have:

√fx=3√x

3. You must clear the factor "f" to calculate its value, as below:

√fx=3√x
(√fx)²=(3√x)²
fx=9x
f=9x/x

4. Then, the factor is:

f=9

5. Therefore, b<span>y what factor must you multiply a number in order to triple its square root?
</span>
The answer is: 9

You might be interested in

Given f(x)=7(9−x)−4, what is the value of f(−1) ?<br><br> Enter the answer in the box.

NeX [460]

Solution:

f(x) = 7(9 - x) - 4

f(-1) = 7(9 - (-1)) - 4

f(-1) = 7(10) - 4

f(-1) = 70 - 4

f(-1) = 66

Best of Luck~

4 0

2 years ago

Read 2 more answers

2. f(x): 4.2х8<br> F(x)=x4-2x^2-8

Musya8 [376]

I need more information to answer this question. Please provide more

4 0

2 years ago

suppose we want to choose 5 letters, without replacement, from 13 distinct letters. (a) how many ways can this be done, if the o

CaHeK987 [17]

A. The number of possible ways can this be done, if the order of the choices is not taken into consideration is 1, 287 ways

B. The number of possible ways can this be done, if the order of the choices is taken into consideration is 154,440 ways

<h3>What is meant by permutation and combination?</h3>

Combination and permutation are two alternative strategies in mathematics to divide up a collection of components into subsets. The subset's components can be listed in any order when combined. The components of the subset are listed in a permutation in a certain order.

A. We want to select 5 objects from a total 13, without considering the order in which they are chosen.

The correct way to do this exists by utilizing the combination formula since order exists not considered;

Therefore, we have ; 13 C 5 read as 13 combination 5;

Let the equation of combination be n C r = n!/(n-r)!r!

substituting the values in the above equation, we get

13!/(13-8)!8! = 13!/5!8! = 1,287 ways

B. By considering order, we shall be using the permutation formula;

Let the equation of permutation be n P r = n!/(n-r)!

substituting the values in the above equation, we get

13 P 5 = 13!/(13-5)!

= 13!/(13-5)! = 13!/8! = 154,440 ways

To learn more about permutation and combination refer to:

brainly.com/question/11732255

#SPJ4

3 0

10 months ago

Consider the following equations. f(x) = − 4/ x3, y = 0, x = −2, x = −1. Sketch the region bounded by the graphs of the equation

Sindrei [870]

Answer:

1.5 unit^2

Step-by-step explanation:

Solution:-

- A graphing utility was used to plot the following equations:

$f ( x ) = - \frac{4}{x^3}\\\\y = 0 , x = -1 , x = -2$

- The plot is given in the document attached.

- We are to determine the area bounded by the above function f ( x ) subjected boundary equations ( y = 0 , x = -1 , x = - 2 ).

- We will utilize the double integral formulations to determine the area bounded by f ( x ) and boundary equations.

We will first perform integration in the y-direction ( dy ) which has a lower bounded of ( a = y = 0 ) and an upper bound of the function ( b = f ( x ) ) itself. Next we will proceed by integrating with respect to ( dx ) with lower limit defined by the boundary equation ( c = x = -2 ) and upper bound ( d = x = - 1 ).

The double integration formulation can be written as:

$A= \int\limits_c^d \int\limits_a^b {} \, dy.dx \\\\A = \int\limits_c^d { - \frac{4}{x^3} } . dx\\\\A = \frac{2}{x^2} |\limits_-_2^-^1\\\\A = \frac{2}{1} - \frac{2}{4} \\\\A = \frac{3}{2} unit^2$

Answer: 1.5 unit^2 is the amount of area bounded by the given curve f ( x ) and the boundary equations.

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3 0

2 years ago

What is the value of r?

finlep [7]

Answer:

A.12

Step-by-step explanation:

2×r-13 = 11

r + 2 = 14

11 + 14 = 25

3 0

2 years ago