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BlackZzzverrR [31]
2 years ago
9

What is the equation of the line in standard form of the graph below?

Mathematics
1 answer:
Mashcka [7]2 years ago
8 0

Answer:

Step-by-step explanation:

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The measure of an angle is 6°. What is the measure of its complementary angle?
stealth61 [152]

Answer:

84 degrees.

Step-by-step explanation:

First, let's define what a complementary angle is. It's when two angles add up to 90 degrees. So we do 90-6=84 and 84+6 does in fact equal 90, so they are complementary.

5 0
3 years ago
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Figure out the slope of the line that passed through each pair of points (4,-11) and (7,-8)​
wlad13 [49]

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slope =  \frac{ - 8 - ( - 11)}{7 - 4}  \\

slope =  \frac{ - 8 + 11}{7 - 4}  \\

slope =  \frac{3}{3}  \\

slope = 1

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4 0
3 years ago
Can someone tell me the right answer to this question pls and thank you
Katena32 [7]

When it comes to graphing, Desmos is a lifesaver!

I believe its B

4 0
3 years ago
The second term of an arithmetic sequence is -39. The rule a, = a -1 + 12 can be used to find the next term of the
siniylev [52]

Step-by-step explanation:

the first one is the correct one

a, = -51+12(n-1)

a(2) = -51+12(2-1)=-39

I hope this helps

Im sure from the answer

but I couldnt explain it exactly

4 0
3 years ago
Read 2 more answers
A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies
RoseWind [281]

Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean weight = 733 grams

            \sigma = standard deviation = 9 grams

Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

                    P(X > x) = 0.05       {where x is the required weight}

                    P( \frac{X-\mu}{\sigma} > \frac{x-733}{9} ) = 0.05

                    P(Z > \frac{x-733}{9} ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

                               \frac{x-733}{9}=1.645

                              {x-733}}=1.645\times 9

                              x = 733 + 14.81

                              x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

8 0
3 years ago
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