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4vir4ik [10]
2 years ago
15

Find the distance between the points (6, -4) and (0, 5). A. 117 B. 37 C. 313−−√ D. 37−−√

Mathematics
1 answer:
Artist 52 [7]2 years ago
5 0

Answer:  Choice A)  \sqrt{117}

Work Shown:

(x_1,y_1) = (6,-4) \text{ and } (x_2, y_2) = (0,5)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(6-0)^2 + (-4-5)^2}\\\\d = \sqrt{(6)^2 + (-9)^2}\\\\d = \sqrt{36 + 81}\\\\d = \sqrt{117}\\\\d = \sqrt{9*13}\\\\d = \sqrt{9}*\sqrt{13}\\\\d = 3\sqrt{13}\\\\d \approx 10.8167\\\\

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Answer:

4b-3b=4+4

b=8

Step-by-step explanation:

Hence, the value of b is 8

#hope it helps

6 0
3 years ago
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dmitriy555 [2]

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8 0
3 years ago
Vector V is shown in the graph below.
Lady_Fox [76]

Answer:

v = -8i - 6j

Step-by-step explanation:

The starting point is (9, 9)

The direction of the vector is the direction of the arrowhead.

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The j is the vertical component.

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8 0
2 years ago
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Why is (x-3) NOT a factor of x3+2x2-5x-6
ivolga24 [154]

As the expression is not equal to zero on x=3, x-3 is not a factor of given expression

Step-by-step explanation:

Given expression is:

x^3+2x^2-5x-6

We have to check if x-3 is a factor of given expression

In order for x-3 to be a factor of expression, we have to put x-3 = 0 => x=3 in expression.

If the expression is zero at x=3 then x-3 is a factor of expression otherwise not.

So putting x=333 in expression

=(3)^3+2(3)^2-5(3)-6\\= 27+2(9) - 15-6\\= 27+18-15-6\\= 45-21\\=24 \neq 0

As the expression is not equal to zero on x=3, x-3 is not a factor of given expression

Keywords: Polynomials, expressions

Learn more about polynomials at:

  • brainly.com/question/4228574
  • brainly.com/question/4279146

#LearnwithBrainly

8 0
3 years ago
Round 6.09933418366 to 4 decimal places
Sergio039 [100]

Answer:

6.113 i believe to be so

6 0
3 years ago
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