what are the x-intercepts of the graph of the function f(x) = x2 4x – 12? (–6, 0), (2,0) (–2, –16), (0, –12) (–6, 0), (–2, –16),
joja [24]
F(x) = x^2 + 4x - 12
x-intercepts are the values of x when y = 0
x^2 + 4x - 12 = 0
(x - 2)(x + 6) = 0
x - 2 = 0 or x + 6 = 0
x = 2 or x = -6
Therefore the x-intercepts are (-6, 0), (2, 0)
Answer:
45
Step-by-step explanation:
A whole circle is 360 so if you divided that by 8 you get 45
Let's plug in the variables one by one.
6g - 2h
plug in 5 for g and 4 for h
6(5) - 2(4)
multiply
30 - 8
subtract
→ 22
20g
plug in 2 for g
20(2)
multiply
40
2(g + 1)
plug in 10 for g
2(10 + 1)
add
2(11)
multiply
→ 22
4g + 5h
plug in 1 for g and 4 for h
4(1) + 5(4)
multiply
4 + 20
add
24
Therefore, the answers that have a value of 22 are 6g - 2h and 2(g + 1)
Answer:
(1.6, 6)
Step-by-step explanation:
y = 6