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Slav-nsk [51]
3 years ago
10

A group of friends had 28 driveways to shovel. If one of them shoveled 1/4 of the driveways, how many driveways did he shovel.

Mathematics
1 answer:
serg [7]3 years ago
3 0

Answer: 7

Step-by-step explanation:

Since we are given the information that a group of friends had 28 driveways to shovel and that one of them shoveled 1/4 of the driveways.

The number of driveways that he shovel will be:

= 1/4 × 28

= 7

Therefore, he shovel 7 driveways.

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Answer:

The quotient = 4x - 17 and the remainder = 54

Step-by-step explanation:

\frac{4x^{2}-5x+3 }{x+3}=4x+\frac{-17x+3}{x+3}

\frac{-17x+3}{x+3}=-17+\frac{54}{x+3}

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Answer:5.7 D

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( - 7a'y + xy + 3x + 2) + (5r²y – 5cy - 6x – 7)
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Answer:

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Question 2 of 15. Step 1 of 1
azamat

9514 1404 393

Answer:

  A = -68.75p +2906.25

Step-by-step explanation:

We can solve for m and b using the given values of A and p.

  1600 = m·19 +b

  2150 = m·11 +b

Subtracting the second equation from the first, we have ...

  -550 = 8m

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Substituting this into the first equation gives ...

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The desired linear equation is ...

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__

<em>Additional comment</em>

Revenue will be maximized at the price that cuts attendance to half the value when the price is 0, about $21.14.

3 0
3 years ago
I need help <br> Please help ASAP
soldi70 [24.7K]

Answer:

The volume of the solid is  1,021m^3

Step-by-step explanation:

1. Cylinder

For find the volume of a cylinder we use the next formula:

V_{cylinder} = \pi h r^2 = \pi \cdot 9m\cdot (5m)^2 \approx 706.86m^3

Then the volume of the cylinder is equal to 706.86m^3

2. Cones

For find the volume of a cone we use the next formula:

V_{cone} = \pi \frac{h}{3} r^2 = \pi \cdot \frac{6m}{3} \cdot (5m)^2 \approx 157.08m^3

However there are two cones so we have to multiply the volume of one cone for two and we get the total volume for the cones which is 314.16m^3

3. Sum of the volumes

Finally we sum the volumes of the cylinder and the cones for get the final result

V_{cylinder} + V_{cones} = 706.86m^3 + 314.16m^3 \approx 1021m^3

So approximating the result is 1021m^3

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2 years ago
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