I don’t get this plsss someone help

Can someone help on both of the questions, i dont get it

o-na [289]

Answer:

A. finished 1km

Step-by-step explanation:

b. 8km per hour

6 0

3 years ago

What is the equation of a line that passes through (-2,1) and is parallel to y=3x-4

Rama09 [41]

If a line is parallel to another, the slopes of both lines are the same. So for this problem, you can infer that the slope of the line you're trying to find is 3.

To find the actual equation of the line, you can use the given coordinates and plug them into the point slope form:

y - y1 = m(x - x1)

plug the given y coordinate into y1 and the given x coordinate into x1. m is the slope, so plug in 3 for m.

y - 1 = 3(x +2) Use distributive property for right side of equation

y - 1 = 3x + 6 add 1 to both sides to cancel -1 on left side of equation and isolate y

Equation of line: y = 3x + 7

3 0

3 years ago

The height of Atlas V rocket used for space lifts was 205 feet. What is the height of a model of Atlas V rocket if the scale fac

KengaRu [80]

Answer: 6.4 feet

Step-by-step explanation:

Height of Atlas V rocket = 205 feet

Ratio of the model = 1:32 = 1/32

Model / Real = 1/32

Since Real height = 205, we put it into the equation and this will be:

Model / Real = 1/32

Model / 205 = 1/32

Model × 32 = 205 × 1

Model = 205/32

Model = 6.4 feet

The height of the model is 6.4 feet.

7 0

2 years ago

PLEASE I NEED HELP

NeTakaya

Answer:

D) y=-1/2x+4

Step-by-step explanation:

D) y=-1/2x+4

In order to be parallel, it has to have the same slope (-1/2). Also, if you plug in (-2,5) for x and y, it does pass through those coordinates.

8 0

3 years ago

The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged

Temka [501]

Answer:

a) 0.283 or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z= $\frac{X-M}{s}$ where

X is the left atrial diameter value we are looking for its z-score

M is the mean left atrial diameter of healthy children (26.7 mm)

s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*= $\frac{24-26.7}{4.7}$ ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*= $\frac{32-26.7}{4.7}$ ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)= $\frac{30-26.7}{4.7}$ ≈ 0.702

z(25)= $\frac{25-26.7}{4.7}$ ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84= $\frac{X-26.7}{4.7}$ solving this equation for X we get X=30.648

5 0

3 years ago