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natali 33 [55]
1 year ago
5

Find the area of circle Y. The image is represented by circle Y with a sector XYZ that has an area of 85.5 square meters. That s

ector has an arc that measures 117 degrees. The radius of the circle is unknown.
Mathematics
1 answer:
pochemuha1 year ago
6 0

Answer:

  263.08 m²

Step-by-step explanation:

The fraction of circle area that a sector represents is proportional to the central angle.

<h3>Proportion</h3>

  circle area/circle angle = sector area/sector angle

  circle area / 360° = 85.5 m² / 117°

Multiplying by 360°, we have ...

  circle area = (360/117)(85.5 m²) = 263.08 m²

The area of the circle is about 263.08 m².

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What two numbers multiplies to 36 and add to negative 21
anastassius [24]
Factor 36 and add them, make sure both are negatie
1+36=37, nope
2+18=20 nope
3+12=15,nope
4+9=13, nope
6+6=12, nope

the closest one is 20

I hope you meant adds to -20, because if you did, then answer is -2 and -18

if you did mean 36 and adds to -21, then the numbers are \frac{-21-3 \sqrt{33} }{2} and \frac{-21+3 \sqrt{33} }{2}, aprox -19.1168 and  -1.8831
6 0
3 years ago
Who can help me answer this question ASAP please and thank you please show work
kotegsom [21]

I'll do the first one to get you started

So we have g(f(x)) which means that we start with g(x) and replace the 'x' with 'f(x)' to get g(f(x))

g(x) = ( x - 4 )/2

g(f(x)) = ( f(x) - 4)/2 .... replace every x with f(x)

g(f(x)) = (2x+4-4)/2 .... replace f(x) on the right side with 2x+4

g(f(x)) = (2x+0)/2

g(f(x)) = (2x)/2

g(f(x)) = 1x/1

g(f(x)) = 1x

g(f(x)) = x

Let me know if you need help with the other one.

4 0
3 years ago
The equation of the line -(11,-12) and (-8,-21)​
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8 0
3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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