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Phantasy [73]
3 years ago
6

40⋅8−10^2 what is the result

Mathematics
2 answers:
svlad2 [7]3 years ago
8 0

Step-by-step answer:

40x8-10^2

40x8-100

320-100

220

Liono4ka [1.6K]3 years ago
7 0

Answer:

220

Step-by-step explanation:

40 x 8 = 320, and 10 squared is 100. 320 - 100 = 220.

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4x+5y=20 in point slope form
Anna35 [415]

Answer:

y = -4/5x - 4

Step-by-step explanation:

y - y1 = m(x-x1)

4x + 5y = 20 ( subtract 4x on both sides)

5y = -4x + 20 (divide by 5 on each side)

y = -4/5x + 4

So we know one point is (0,4) y-intercept

now plug in (0,4)

y - 4 = -4/5(x-0) (Distribute -4/5 to x - 0)

y - 4 = -4/5x (now add 4 on each side)

y = -4/5x - 4

4 0
3 years ago
Read 2 more answers
It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet. A transportat
Mrrafil [7]

Answer:

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 120 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 120  

Alternative hypothesis:\mu \neq 120  

Part 2

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{114-120}{\frac{22}{\sqrt{36}}}=-1.636    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z  

Step-by-step explanation:

Data given and notation  

\bar X=114 represent the sample mean  

\sigma=22 represent the population standard deviation

n=36 sample size  

\mu_o =120 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part 1

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 120 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 120  

Alternative hypothesis:\mu \neq 120  

If we analyze the size for the sample is > 30 and we  know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part 2

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{114-120}{\frac{22}{\sqrt{36}}}=-1.636    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z  

8 0
3 years ago
PLEASE HELP. <br> if v1….
Rainbow [258]
I believe the answer is 4.4
6 0
2 years ago
Please help and thank you. ​
Marina CMI [18]

Answer:

4.

  • 400 ft elevation at 1 km and 3 km from the start
  • 300 ft/km average rate of change over the first 4 km

5.

  • length = 3.5 cm
  • width = 3.5 cm
  • height = 7.0 cm

6.

  • 6 mo: $1018.14
  • 5 yrs: $1196.89
  • avg incr: $3.28 per month

Step-by-step explanation:

<h3>4.</h3>

A graphing calculator is handy for solving problems involving cubic polynomials. You're interested in where the elevation is 400 ft. Since the value of f(x) is in hundreds of feet, you want to find x such that f(x) = 4.

Values of x where that is the case are x=1 and x=3, representing distances of 1 km and 3 km from the start of the road.

The average rate of change of elevation is the difference in elevation divided by the difference in distance from the start:

  average rate of change = (f(4) -f(0) hundred ft)/((4 - 0) km)

  = (19 -7)/4 hundred feet/km

  = 12/4  hundred feet/km = 300 ft/km

___

<h3>5.</h3>

You want to find x when ...

  A(x) = 122.5 cm²

  10x² = 122.5 cm² . . . . substitute the given expression for A(x)

  x² = 12.25 cm² . . . . . . divide by 10

  x = √(12.25 cm²) = 3.5 cm . . . . take the square root

The diagram tells you ...

  length = width = x = 3.5 cm

  height = 2x = 7.0 cm

___

<h3>6.</h3>

Evaluate the given expression for the different values of m:

  $1000·1.003^6 ≈ $1018.14 . . . . 6-month value

  $1000·1.003^60 ≈ $1196.89 . . . . 5-year value

The increase is $1196.89 -1000.00 = $196.89. That increase took place over 60 months, so the average increase per month is ...

  $196.89/(60 mo) ≈ $3.28 per mo . . . . average per month over 5 years

8 0
3 years ago
Find the total cost of 5 bales of hay at $2.75 per bale and 2 bags of potatoes at $2.90 per bag.
Elan Coil [88]

Answer: $19.55

Step-by-step explanation:

  1. 2.75 * 5 = 13.75.
  2. 2.90 * 2 = 5.80
  3. 13.75 + 5.80 = 19.55
5 0
3 years ago
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