Answer:
0.456 M
Explanation:
Step 1: Write the balanced neutralization equation
HNO₂ + KOH ⇒ KNO₂ + H₂O
Step 2: Calculate the reacting moles of KOH
9.26 mL of 1.235 M KOH react.
0.00926 L × 1.235 mol/L = 0.0114 mol
Step 3: Calculate the reacting moles of HNO₂
The molar ratio of HNO₂ to KOH is 1:1. The reacting moles of HNO₂ are 1/1 × 0.0114 mol = 0.0114 mol.
Step 4: Calculate the initial concentration of HNO₂
0.0114 moles of HNO₂ are in 25.0 mL of solution.
[HNO₂] = 0.0114 mol / 0.0250 L = 0.456 M
The answer is d I think. Don’t quote me if I’m wrong
Answer:
We have the final answer as

Explanation:
To find the energy of a photon of this light we use the formula
<h3>E = hf</h3>
where
E is the energy
f is the frequency
h is the Planck's constant which is
6.626 × 10-³⁴ Js
From the question
f = 7.08×10¹⁴ Hz
We have
E = 7.08×10¹⁴ × 6.626 × 10-³⁴
We have the final answer as

Hope this helps you
Answer:

Explanation:
Heat of combustion of
= -1366.8 kJ/mol
Heat of formation of
= -393.5 kJ/mol
Heat of formation of
= -285.8 kJ/mol
The reaction is

Assuming
is the standard enthalpy of formation of ethanol

The standard enthalpy of formation of ethanol is
.