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Marina CMI [18]
2 years ago
7

What is the concentration of pb 2 ions in a solution prepared by adding 5. 00 g of lead(ii) iodide to 500. ml of 0. 150 m ki? [

k sp(pbi 2) =1. 4 × 10 –8]
Chemistry
1 answer:
sashaice [31]2 years ago
4 0

37.1×10−8M is the concentration of pb 2 ions in a solution prepared by adding 5. 00 g of lead(ii) iodide to 500. ml of 0. 150 m ki? [ k sp(pbi 2) =1. 4 × 10 –8] by common ion effect.

A phenomenon known as the "common ion effect" allows for the modification of a salt's molar solubility by adding another salt in which one ion dissociates in solution and maintains equilibrium with the undissociated salt.

The term "common-ion effect" describes the reduction in solubility of an ionic precipitate caused by the addition of a soluble molecule that shares an ion with the precipitate to the solution. Le principle for the equilibrium response of ionic association/dissociation leads to this behavior.

To learn more about the "common-ion effect" please visit-
brainly.com/question/13194653
#SPJ4

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230g sample of a compound contains 136.6g carbon, 26.4g hydrogen, and 31.8g nitrogen. What is masspercentif oxygen
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Answer:

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Explanation:

Step 1: Given data

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Step 2: Calculate the mass of oxygen (mO)

The mass of the sample is equal to the sum of the masses of all the elements.

ms = mC + mH + mN + mO

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Step 3: Calculate the mass percent of oxygen

%O = (mO / ms) × 100% = (35.2 g / 230 g) × 100% = 15.3 %

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