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Soloha48 [4]
3 years ago
7

Both Jacques Charles and Joseph Louis Guy-Lussac were avid balloonists. In his original flight in 1783, Jacques Charles used a b

alloon that contained approximately 31100 L of H2. He generated the H2 using the reaction between iron and hydrochloric acid: Fe(s)+2HCl(aq)→FeCl2(aq)+H2(g)
How many kilograms of iron were needed to produce this volume of H2 if the temperature was 21 ∘C? (For simplicity, assume that the pressure experienced by the balloon will be 1.00 atm.)
Chemistry
1 answer:
daser333 [38]3 years ago
3 0

Answer:

m_{Fe}=71.982 kg

Explanation:

First of all, we need  to calculate the moles of H2. Assuming the H2 is an ideal gas:

n=\frac{P*V}{T*R}

n=\frac{1atm*31100L}{294K*0.082 L*atm*mol^{-1}*K^{-1}}

n=1290 mol

Now, to produce 1 mol of H2 is required 1 mol of Fe:

m_{Fe}=n*M=1290mol*\{55.8 g}{mol}

m_{Fe}=71982 g=71.982 kg

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<span>A chemical reaction is required to separate the substances in a compound. The components of a mixture can be separated based on their physical properties using techniques like filtration or distillation.</span>
8 0
3 years ago
Sort these isotopes by whether they are most likely to undergo fusion or fission.
Maslowich

Answer:

Uranium-233- fission

Plutonium-239- fission

Plutonium-241- fission

Hydrogen-3 fusion

Hydrogen-1 fusion

Helium-3 fusion

Explanation:

In nuclear fission, heavy nuclear disintegrate into smaller nuclei when bombarded with particles such as neutrons. Fission reaction is common among nuclei having a high atomic number such as plutonium and uranium.

Fusion occurs between two light nuclei such as hydrogen or helium. It involves the combination of two lighter elements to give a heavier element with the release of tremendous amount of energy.

4 0
3 years ago
How many grams of CuSO4 • 5H2O do you need to make 0.8 L of a 0.6 M solution
Bumek [7]
<h3><u>Unders</u><u>tanding</u><u> </u><u>the</u><u> </u><u>conc</u><u>ept</u><u>:</u><u>-</u></h3>

Here the concept of Molarity used .We will put the formula of Molarity then we find moles of copper sulphate .Then we can find the.Given weight of Copper sulphate.So let's do

<h3>Solution:-</h3>

  • Volume of Solvent=0.8L
  • Molarity=0.6M

We know

\boxed{\sf Molarity=\dfrac{Moles\:of\: solute}{Volume\:of\: Solvent \:in\;L}}

\\ \rm\longmapsto Moles\:of\: solute=Molarity\times Volume\:of\: Solvent\:in\:L

\\ \rm\longmapsto Moles\:of\: Solute=0.8(0.6)

\\ \rm\longmapsto Moles\:of\: Solute=0.48mol

Now

Molar Mass of Solute:-

\\ \rm\longmapsto CuSO_4.5H_2O

\\ \rm\longmapsto 65u+32u+4(16u)+5(2\times 1u+16u)

\\ \rm\longmapsto 96u+64u+5(2+16)

\\ \rm\longmapsto 160u+90u

\\ \rm\longmapsto 250u

\\ \rm\longmapsto 250g/mol

Now

\boxed{\sf No\:of\:moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \rm\longmapsto Given\:Mass=No\:of\:Moles\times Molar\:Mass

\\ \rm\longmapsto Given\:Mass=250(0.48)

\\ \rm\longmapsto Given\:Mass=120g

8 0
3 years ago
Brian is testing to see how much water plants need. Why is it important that Brian includes a control group? A) To observe wheth
bija089 [108]

Answer: B or C

Explanation: The question does not include the variable or steps Brian is using so either one could be correct. It has to be the one that he is controlling though. This is because a control group is used to rule out any alternate explanations. Therefore the answer should be the one that he is trying to test out.

7 0
3 years ago
The number of particles in 1 mole of hydrogen gas is ________.
ivanzaharov [21]
Hidrogen gas is a diatomic gas, this is H2, which means that one molecule of gas has two atoms (every molecule of hydrogen gas consists in H2).

The particles in gases are the molecules, not atoms.

So, every molecule is a particle, and when you are told that you have 1 mole of hygrogen gas means that you have 1 mole of H2 molecules which is the same that 1 mole of particles.

Therefore, the answer is one mole.
3 0
3 years ago
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