Based on the total number of people who want the steakhouse option, the probability that a student will not want the seafoodbuffet if they want the steakhouse option is 24%
<h3>What is the probability of the students' choice?</h3><h3 />
The probability that a student does not want the seafood buffet given that they want the steakhouse option is:
= Number of people who want steakhouse but not seafood / Total surveyed
Solving gives:
= 9 / (16 + 8 + 9 + 4)
= 9 / 37
= 24%
Full question is:
If a student wants the steakhouse option, what is the probability that they will not want the seafoodbuffet?
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Divide the first equation by 2 and add the result to the second equation. This will eliminate x.
... (-4x -2y)/2 + (2x +4y) = (-12)/2 +(-12)
... 3y = -18 . . . . . collect terms
... y = -6 . . . . . . . divide by 3
Substitute this into either equation to find x. Let's use the second equation, where the coefficient of x is positive.
... 2x +4(-6) = -12
... 2x = 12 . . . . . . . . add 24
... x = 6 . . . . . . . . . . divide by 2
The solution is (x, y) = (6, -6).
57.29 you do 48.55 times .18 which =8.74 then add the tip with the initial cost 8.74+48.55 =57.29 to get your answer 57.29
Answer:
216
Step-by-step explanation:
108 x 2 = 216
Ughhh I’m not totally sure I’m sorry I tried looking it up for you
