Hmm... interesting topic you're writing about here!
Well, for this essay, there must be specific criteria, correct? I'll make some suggestions, but of course you don't have to go by them if you don't like 'em. So... here they are!:
- List the physical and chemical properties of glue
- List the physical and chemical properties of liquid corn starch
- Compare and contrast the physical and chemical properties of glue with the physical and chemical properties of liquid corn starch
- You can conduct some experiments with the two substances also! You can mix the two together and see how they react with each other, and incorporate the results of the experiment into your essay.
- You can mix glue with some other liquid substances too, and incorporate your results into your essay. You can see whether each substance the glue mixes with creates a homogeneous or heterogeneous mixture, etc.
- You can mix liquid corn starch with some other liquid substances too, and incorporate your results into your essay. You can see whether each substance the liquid corn starch mixes with creates a homogeneous or heterogeneous mixture, etc.
That's all I can come up with at the moment. Maybe you'll take some of these suggestions into consideration...? Anyhow, I hope I helped somehow! :)
<h3><u>Answer;</u></h3>
0.5 M HBr, pOH = 13.5 ; Has the lowest pH
<h3><u>Explanation;</u></h3>
From the question;
pH = -Log [OH]
or pH = 14 - pOH
Therefore;
For 0.5 M HBr
[H+] = 0.5 M
pH = - Log [0.5]
= 0.30
For; pOH = 13.5
pH = 14 - pOH
= 14 -13.5
= 0.5
For; 0.05 M HCl
pH = - log [H+]
[H+] = 0.05
pH = - Log [0.05]
= 1.30
For; pOH = 12.7
pH = 14 -pOH
= 14 -12.7
= 1.30
For; 0.005 M KOH,
pOH = - log [OH]
[OH-] = 0.005
pOH = - Log 0.005
= 2.30
pH = 14 - 2.30
= 11.7
For; pOH = 2.3
pH = 14 -pOH
= 14- 2.3
= 11.7
pH of solution = 13.033
<h3>Further explanation</h3>
Given
2.31 g Ba(OH)₂
250 ml water
Required
pH of solution
Solution
Barium hydroxide is fully ionized, means that Ba(OH)₂ is a strong base
So we use a strong base formula to find the pH
[OH ⁻] = b. Mb where
b = number of OH⁻
/base valence
Mb = strong base concentration
Molarity of Ba(OH)₂(MW=171.34 g/mol) :
Ba(OH)₂ ⇒ Ba²⁺ + 2OH⁻(b=valence=2)
[OH⁻]= 2 . 0.054
[OH⁻] = 0.108
pOH= - log 0.108
pOH=0.967
pOH+pH=14
pH=14-0.967
pH=13.033
huh???? thats makes ni sencse
