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vlada-n [284]
3 years ago
6

Round off 1.732 kg to three significant figures. Express your answer with the appropriate units, Value and Units.

Chemistry
1 answer:
butalik [34]3 years ago
8 0

Answer:

1.73 \: kg \\ to \: 3 \: sf

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In atomic physics and quantum chemistry , the electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s 2 2s 2 2p 6, using the notation explained below.

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Chemistry is the definition​
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4 years ago
31. calculate the amount of energy released as heat by the freezing of 13.3 g of a liquid substance, given that the substance ha
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From the calculations, the heat of fusion of the substance is 0.73 kJ

<h3>What is is the heat of freezing?</h3>

The heat of freezing is the energy released when the substance is converted from liquid to solid.

Now we know that the molar mass of the substance is 82.9 g/mol  hence the number of moles of the substance is;  13.3 g /82.9 g/mol  = 0.16 moles

Now the heat of fusion shall be;

H = 4.60 kj/mol * 0.16 moles

H = 0.73 kJ

Learn more about freezing:brainly.com/question/3121416

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5 0
2 years ago
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Liono4ka [1.6K]

Answer:

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Explanation:

6 0
3 years ago
An aluminum kettle weights 1.05 kg and has a heat capacity of 0.9211 J over grams Celsius how much heat is required to increase
Serggg [28]

Answer:

64799.4 J

Explanation:

The following data were obtained from the question:

Mass (M) = 1.05 kg = 1.05 x 1000 = 1050g

Specific heat capacity (C) = 0.9211 J/g°C

Initial temperature (T1) = 23°C

Final temperature (T2) = 90°C

Change in temperature (ΔT) = T2 – T1 =

90°C – 23°C = 67°C

Heat required (Q) =....?

The heat required to increase the temperature of the kettle can b obtain as follow:

Q = MCΔT

Q = 1050 x 0.9211 x 67

Q = 64799.4 J

Therefore, 64799.4 J of heat is required to increase th temperature of the kettle from 23°C to 90°C.

4 0
3 years ago
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