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2 years ago

7

PLEASE HELP URGENT‼️‼️

1 answer:

Dima020 [189]2 years ago

3 0

Part A

(3x)^2*x^4

(3x)*(3x)*x^4 .... expand out (3x)^2

(3*3)*(x*x*x^4)

9x^6

Answer: 9x^6

============================================

Part B

It appears that Tonya forgot to square the 3 term and had this as her steps

(3x)^2*x^4

3x^2*x^4

3x^(2*4)

3x^8

Which is incorrect as the answer in part A indicates.

Not only is the '3' part wrong, but also the exponent of 8. Instead of multiplying the exponents, she should have added them.

The rule is a^b*a^c = a^(b+c). In this case, a = x, b = 2 and c = 4.

So x^2*x^4 = x^(2+4) = x^6

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Please help..I dont get this and please Dont put a Link below please.

lianna [129]

Answer:

x = 27, y = 74

Step-by-step explanation:

Hi again :)

Since the angles of 5x + 4 and the one adjacent to x = 14 are corresponding angles, they are equal. That means that (5x + 4) + (x + 14) = 180 degrees.

5x + 4 + x + 14 = 180

6x + 18 = 180

6x = 162

x = 27

Also, the angle (5x + 4) and (2y - 9) are vertical angles, they are equal in value. We know the value of x now, so we'll substitute that in and solve for y.

5(27) + 4 = 2y - 9

135 + 4 = 2y - 9

139 = 2y - 9

148 = 2y

y = 74

As always, lmk if you have questions.

3 0

3 years ago

Statistics endeavors to:

Aleks04 [339]

Answer:

c

Step-by-step explanation:

8 0

3 years ago

9-x/5=3. Solve for x

kari74 [83]

Answer:

$\boxed{\boxed{\sf x=-6}}$

Step-by-step explanation:

$\sf \cfrac{9-x}{5}=3$

$\sf \cfrac{5\left(9-x\right)}{5}=3\times \:5$

$\sf 9-x=15$

$\sf 9-x-9=15-9$

$\sf -x=6$

$\sf \cfrac{-x}{-1}=\cfrac{6}{-1}$

$\sf x=-6$

<h3>⚝──⭒─⭑─⭒──⚝⚝──⭒─⭑─⭒──⚝</h3>

4 0

2 years ago

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago

Hru im in an amazing mood help meeeeeeeeeeeee plzzzzzzzzzzzz

strojnjashka [21]

Answer:

I think its A

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers