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2 years ago

Question 6

Chemistry

1 answer:

hodyreva [135]2 years ago

4 0

Answer:

0.00688 moles

Explanation:

The molarity ratio looks like this:

Molarity = moles / volume (L)

After you convert mL to L, you can plug the values into the equation and simplify to find moles.

27.5 mL / 1,000 = 0.0275 L

Molarity = moles / volume <----- Molarity ratio

0.250 M = moles / 0.0275 L <----- Insert values

0.00688 = moles <----- Multiply both sides by 0.0275

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The equator being it is the hottest place on the earth

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3 years ago

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blsea [12.9K]

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3 years ago

What are the products of the acid-base reaction between HNO3 and NaOH? A. H2O and NaNO3 B. NaH and NO3OH C. HNOH and NaO3 D. NaO

Otrada [13]

Answer:- A. $H_2O$ and $NaNO_3$

Explanations:- In general, $acid+base\rightarrow salt+water$

In acid-base reaction the acid gives hydrogen ion and the base gives hydroxide ion and these ions combine to form water. Rest of the ions from acid and base combine to form the salt.

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The reaction is shown as:

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3 years ago

A solution of nitrous acid and potassium nitrite acts as a buffer due to reactions that occur within the solution when a strong

Ghella [55]

Answer:

a. NO₂⁻ + H⁺ → HNO₂

b. HNO₂ + OH⁻ → NO₂⁻ + H₂O

Explanation:

A buffer is defined as an aqueous mixture of a weak acid and its conjugate base or vice versa.

The buffer of the problem is HNO₂/NO₂⁻ <em>where nitrous acid is the weak acid and NO₂⁻ is its conjugate base.</em>

a. When a acid is added to a buffer as the buffer of the problem, the conjugate base will react with the acid, to produce the weak acid, thus:

NO₂⁻ + HCl → HNO₂ + Cl⁻

Ionic equation is:

NO₂⁻ + H⁺ + Cl⁻ → HNO₂ + Cl⁻

In the net ionic equation, you avoid the ions that don't react, that is:

b. In the same way, the weak acid will react with the strong acid producing water and the conjugate base, thus:

HNO₂ + NaOH → NO₂⁻ + H₂O + Na⁺

The ionic equation is:

HNO₂ + Na⁺ + OH⁻ → NO₂⁻ + H₂O + Na⁺

And the net ionic equation is:

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3 years ago

What would be the resulting molarity of a solution made by dissolving 21.9 grams of KCl in enough water to make an 869-millilite

viktelen [127]

Molar mass KCl = <span>74.5513 g/mol

Number of moles:

21.9 / 74.5513 => 0.293 moles

Volume = 869 mL / 1000 => 0.869 L

Molarity = moles / Volume

Molarity = 0.293 / 0.869

=> 0.337 M</span>

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4 years ago