For this problem, we use the Beer Lambert's Law. Its usual equation is:
A = ∈LC
where
A is the absorbance
∈ is the molar absorptivity
L is the path length
C is the concentration of the sample solution
As you notice, we only have to find the absorbance. But since we are not given with the molar absorptivity, we will have to use the modified equation that relates % transmittance to absorbance:
A = 2 - log(%T)
A = 2 - log(27.3)
A = 0.5638
V1 = 445ml V2 = 499ml
T1 = 274 K T2 = ?
By Charles Law,
V1/T1 = V2/T2
445/274 = 499/T2
By solving we get,
T2 = 307.25 K
To be honest No not at all
The oxidation-reduction reaction from the reactions above is
ZnS(s) + 2O2(g) ------ ZnSO4(s)
<h3>What is redox reactions?</h3>
Oxidation-reduction or redox reaction is the type of chemical reaction in which oxidation states of substrate changes
So therefore, the oxidation-reduction reaction from the reactions above is
ZnS(s) + 2O2(g) ------ ZnSO4(s)
Learn more about oxidation-reduction reactions:
brainly.com/question/10668495
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Answer:
The name of the phase change is;
Sublimation.
Explanation:
CO₂(s) + energy ⇒ CO₂(g)
Sublimation is the transition of a substance from its solid state to the gaseous state without first turning to a liquid due the high rate of absorption of of thermal energy of the substance such that the substance does not melt first.
As such sublimation is the endothermic process taking place at a temperature and pressure lower than the triple point of the substance in the substance's phase diagram. The triple point is the lowest temperature and pressure at which a substance can exist as a liquid.
