Answer:
The metallic oxide is Li₂O
Explanation:
Let the metallic oxide be M₂O
Thus;
M₂O + H₂ = 2M + H₂O
Molar mass of M₂O = (2x + 16)
We assume Molar mass of M to be x.
We are told that 5.00 g of the metallic oxide produces 2.32 g of the metal.
By proportion, we can write the following;
5g of M₂O × (1 mole of M₂O/(2x + 16)) × (2 moles of M/1 mole of M₂O) = 2.32 g of M × 1 mole of M/x g of M
This cancels out to give us;
10/(2x + 16) = 2.32/x
Cross multiply to get;
10x = 2.32(2x + 16)
10x = 4.64x + 37.12
10x - 4.64x = 37.12
5.36x = 37.12
x = 37.12/5.36
x = 6.925 g/mol
The metal with a molar mass closest to this value of x is Lithium which has a molar mass of 6.94 g/mol
Thus the metal is Lithium and as such the metallic oxide is Li₂O
Including the alkanes, oils , fats and greasy substances in general
Because the Earth<span> is a sphere, the surface gets much more intense sunlight, hence heat, at the equator than at the poles.</span>
The distribution of heat around the globe, and through the year, coupled with the physical properties of air, produce a distinctive pattern of climatic zones.
The answer is that they all have metallic structures
Answer:
carbon dioxide and water
Explanation:
Example: Combustion of Methane (CH₄(g))
CH₄(g) + 2O₂(g) => CO₂(g) + 2H₂O(g)**
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Note: The combustion of any hydrocarbon produces CO₂ & H₂O. That is,
Ethane (C₂H₆) + O₂ => CO₂(g) + H₂O(g)
Propane (C₃H₈) + O₂ => CO₂(g) + H₂O(g)
Butane (C₄H₁₀) + O₂ => CO₂(g) + H₂O(g)
The issue remaining is to balance the reaction equation. For these type equation balance Carbon 1st, then Hydrogen and finish with Oxygen. Balancing in this order leaves Oxygen which can be balanced using fractions. If problem requires lowest whole number ratios of elements, simply multiply entire equation by 2 to get standard equation*
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*Standard Equation is defined as the smallest whole number ratios of elements. The 'standard equation' is significant in that it is assumed to be at STP conditions; i.e., 0⁰C (=273K) & 1.0 Atmosphere pressure.
- Ethane (C₂H₆) + 7/2O₂(g) => 2CO₂(g) + 3H₂O(g)
=> 2C₂H₆ + 7O₂(g) => 4CO₂(g) + 6H₂O(g) <= Standard Form of Rxn
- Propane (C₃H₈) + 5O₂(g) => 3CO₂(g) + 4H₂O(g) <= Standard Form of Rxn (no need to balance with the '2' multiple)
- Butane (C₄H₁₀) + 13/2O₂ => 4CO₂(g) + 5H₂O(g)
=> 2C₃H₈ + 13O₂(g) => 4CO₂(g) + 5H₂O(g) <= Standard Form of Rxn
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**Also, note that water, H₂O(g), is listed as a gas. In some cases it will be listed as a liquid, H₂O(l).
