Answer:Well, if you mean atoms, it has 2 Hydrogen atoms and 1 Oxygen.
Explanation:Water is H20 therefore, it has 2 Hydrogen atoms and 1 Oxygen. Water isn't made up of particles, they are made of atoms.
Answer:
pH + pOH = 14, [H₃0⁺] [0H⁻] = 10⁻¹⁴
Explanation:
When it comes to questions involving pH, the equations used are;
[H₃0⁺] [0H⁻] = 10⁻¹⁴
This equation shows the concentration of hydroxonium ions alongside that of the hydroxide ions.
pH + pOH = 14
If the value of either the pH of the pOH is know,one can calculate the value of the other using this equation.
Answer:
= 200 mL
Explanation:
Using the dilution formula;
M1V1 = M2V2 ;
Where, M1 is the concentration before dilution, V2 is the volume before dilution, while M2 is the concentration after dilution and V2 is the volume after dilution.
M1 = 2.0 M
V1 = 50 mL
M2 = 0.50 M
V2 = ?
V2 = M1V1/M2
= ( 2.0 × 50 )/ 0.5
= 200 mL
Therefore, the volume after dilution will be, 200 mL
A transverse and longitudinal wave combine to form a Water Wave.
For 1. 00 l of an aqueous buffer containing 60. 0 mmol of acetic acid (pa=4. 76) and 40. 0 mmol of acetate, the pH of this buffer is 4.58.
<h3>What is handerson Hasselbalch equation? </h3>
It is expressed as:
pH = pKa + log [A-]/[HA]
where,
[A-] is the molar concentration of conjugate base
[HA] is the molar concentration of weak acid
Given,
pKa = 4.76
<h3>Calculation of concentration:</h3>
C = n/V
= 60/1000
= 0.06M
C = 40/1000
= 0.04M
Now, substituting values in equation we get,
pH = 4.76 + log(0.04/0.06)
pH = 4.76 + (-0.176)
pH = 4.58
Thus by using Henderson Hasselbalch equation we find the value of pH of the buffer is 4.58.
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