Answer:
18
Step-by-step explanation:
Given that:
y∞ xz
y=kxz. Where k is constant
When z=196 and x= 2 then y= 7
7=(196)(2)k
7=392k
k=1/56
There fore y=(1/56)xz
When x=3 and z =336
y=(1/56)xz
y=(1/56)(336)(3)
y=18
-2
explanation:
coefficient is the number in front of the term it's asking for. so the number in front of x² would be the -2.
- another tip the b's represents x in that equation!!
Answer:
Option D. 11√6/2
Step-by-step explanation:
We'll begin by calculating the side opposite to angle 60°.
This is illustrated below:
Angle θ = 60°
Opposite =?
Hypothenus = 11
Using the sine ratio, we can obtain the side opposite to angle 60° as follow:
Sine θ = Opposite/Hypothenus
Sine 60 = Opposite /11
Cross multiply
Opposite = 11 × Sine 60
Sine 60 = √3/2
Opposite = 11 × √3/2
Opposite = 11√3/2
Finally, we shall determine the value of x as follow:
Angle θ = 45°
Opposite = 11√3/2
Hypothenus = x
Using the sine ratio, we can obtain the value of x as shown below:
Sine θ = Opposite/Hypothenus
Sine 45° = 11√3/2 /x
Cross multiply
x × Sine 45° = 11√3/2
Sine 45° = 1/√2
x × 1/√2 = 11√3/2
x/√2 = 11√3/2
Multiply through by √2
x = √2 × 11√3/2
x = 11√6/2
Answer: x=25
Step-by-step explanation:
7+x=32 (subtract 7)
x=25
Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
