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weqwewe [10]
2 years ago
12

Suppose it costs $43 to roll a pair of dice. you get paid $6 times the sum of the numbers that appear on the dice. is it a fair

game?
Mathematics
1 answer:
lutik1710 [3]2 years ago
7 0

The game is not fair as 6 times the expected sum is less than the cost, $43.

In the question, we are asked if the game is fair.

For the game to be fair, 6 times the expected sum for the pair from the game has to be greater than or equal to $43, that is,

6E(X) ≥ 43.

The expected sum for the pair, E(X) can be calculated using the formula,

E(X) = ∑x.p(x),

or, E(X) = 1/18 + 1/6 + 1/3 + 5/9 + 1/6 + 7/9 + 10/9 + 1 + 5/6 + 11/18 + 1/3,

or, E(X) = 107/18.

Now, 6E(X) = 6*(107/18) = 107/3 = 35.67.

Since, the total return from the game is $35.67, which is less than the cost of $43, the game is not fair.

Learn more about expected return from a game at

brainly.com/question/24855677

#SPJ4

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What is the answer for I=E/R for E
Elden [556K]

http://lianmath.com/describe-a-serie-of-shifts-that-translates-the-graph-yx-93-4-back-onto-the-graph-of-yx-3/


7 0
3 years ago
In a set of 25 aluminum castings, four castings are defective (D), and the remaining twenty-one are good (G). A quality control
lianna [129]

Answer:

The sample space for selecting the group to test contains <u>2,300</u> elementary events.

Step-by-step explanation:

There are a total of <em>N</em> = 25 aluminum castings.

Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).

It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!(n-k)!}

Compute the number of samples that are possible as follows:

{25\choose 3}=\frac{25!}{3!\times (25-3)!}

      =\frac{25\times 24\times 23\times 22!}{3!\times 22!}\\\\=\frac{25\times 24\times 23}{3\times 2\times 1}\\\\=2300

The sample space for selecting the group to test contains <u>2,300</u> elementary events.

6 0
3 years ago
Simplify 12/5(10/3b+15/4) .
Elodia [21]
Step 1. Simplify 10/3b to 10b/3
12/5(10b/3 + 15/4)
Step 2. Distribute 
8b + 9

7 0
3 years ago
Read 2 more answers
OMG PLS HELP WITH THIS IM PANICKING OMG I GOT A F IN MATH MY MOM JUST YELLED AT ME IM CRYING PLS HELP WITH THS-
andre [41]

Answer:

4. 50,000 square miles

5. The office would round to $800,000 instead of $700,000 because they would lose that needed $35,495. If they rounded down, their budget would be cut short, and they won’t have enough money for the office.

6. Five numbers that could also be the population: 577,777; 575,555; 578,999: 578,787; 581,545.

7. 600,000

8.584,000

9. 260,000

Step-by-step explanation:

4. In this question, we’re rounding the number, “54,555” go the nearest ten thousand. When rounding numbers you look at the number next to the digit your rounding. In this case, since the second number is not 5 or higher, we round it to 50,000 as that’s closer than 60,000.

5. Like I stated above: if they round to the lowest amount, they won’t have enough money to but what they need. Therefore, even if according to rounding it needs to be lower, it will not be beneficial to the company.

6. This are all possible numbers cause they can all by round to 580,000 AND 600,000

7. Since the number next to six is not five or higher, we round it to the closest number which is 600,000.

8. Since the number next to 3 is 5, we round it to the higher number. So it’s 584,000

9. Since the number next to the underlined nunber is 6, we round it to the closest number which is 260,000

If you have any more questions, you can ask me :)

8 0
3 years ago
Suppose we want to choose colors, without replacement, from the colors red, blue, green, and purple.
DerKrebs [107]

The number of ways when the choice is not relevant is 4

<h3>How to determine the number of ways?</h3>

The number of colors are:

Colors, n = 4

The color to choose are:

r = 3

<u>Relevant choice</u>

When the choice is relevant, we have:

Ways = ^nP_r

This gives

Ways = ^4P_3

Evaluate

Ways = 24

Hence, the number of ways when the choice is relevant is 24

<u>Not relevant choice</u>

When the choice is not relevant, we have:

Ways = ^nC_r

This gives

Ways = ^4C_3

Evaluate

Ways = 4

Hence, the number of ways when the choice is not relevant is 4

Read more about combination at:

brainly.com/question/11732255

#SPJ1

4 0
2 years ago
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