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weqwewe [10]
2 years ago
12

Suppose it costs $43 to roll a pair of dice. you get paid $6 times the sum of the numbers that appear on the dice. is it a fair

game?
Mathematics
1 answer:
lutik1710 [3]2 years ago
7 0

The game is not fair as 6 times the expected sum is less than the cost, $43.

In the question, we are asked if the game is fair.

For the game to be fair, 6 times the expected sum for the pair from the game has to be greater than or equal to $43, that is,

6E(X) ≥ 43.

The expected sum for the pair, E(X) can be calculated using the formula,

E(X) = ∑x.p(x),

or, E(X) = 1/18 + 1/6 + 1/3 + 5/9 + 1/6 + 7/9 + 10/9 + 1 + 5/6 + 11/18 + 1/3,

or, E(X) = 107/18.

Now, 6E(X) = 6*(107/18) = 107/3 = 35.67.

Since, the total return from the game is $35.67, which is less than the cost of $43, the game is not fair.

Learn more about expected return from a game at

brainly.com/question/24855677

#SPJ4

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Harman [31]
Answer: 41/10 or 4.1 or 4 1/10

explanation: multiple each fraction by the number on the bottom and simplify.
6 0
3 years ago
A resident of Bayport claims to the City Council that the proportion of Westside residents
Kazeer [188]

Answer:

The test statistics is  z =  -1.56  

The p-value is   p-value =  0.05938

Step-by-step explanation:

From the question we are told  

   The West side sample  size is n_1  =  578

    The  number of residents on the West side with income below poverty level is k  = 76

    The East side sample size  n_2=688

  The  number of residents on the East side with income below poverty level is u  = 112

   The null hypothesis is  H_o  :  p_1 = p_2

    The alternative hypothesis is  H_a :  p_1 <  p_2

Generally the sample proportion of  West side is  

     \^{p} _1 = \frac{k}{n_1}

=>   \^{p} _1 = \frac{76}{578}

=>   \^{p} _1 =  0.1315

Generally the sample proportion of  West side is  

     \^{p} _2 = \frac{u}{n_2}

=>   \^{p} _2 = \frac{112}{688}

=>   \^{p} _2 =  0.1628

 Generally the pooled sample proportion is mathematically represented as

    p = \frac{k + u}{ n_1 + n_2 }

=>  p = \frac{76 + 112}{ 578 + 688 }

=>  p =0.1485

Generally the test statistics is mathematically represented as

z = \frac{\^ {p}_1 - \^{p}_2}{\sqrt{p(1- p) [\frac{1}{n_1 } + \frac{1}{n_2}  ]}  }

=> z = \frac{ 0.1315  - 0.1628 }{\sqrt{0.1485(1-0.1485) [\frac{1}{578} + \frac{1}{688}  ]}  }  

=> z =  -1.56  

Generally the p-value  is mathematically represented as

          p-value =  P(z <  -1.56 )

From z-table  

         P(z <  -1.56 ) =  0.05938

So

     p-value =  0.05938

3 0
3 years ago
1. Find the sum of the measures of the interior angles of a convex 11-gon.
OleMash [197]

Answer:

The measure of the sum of interior angles of a 11-gon is 1620^{o}.

Each interior angle is approximately 147.273^{o}.

Step-by-step explanation:

A convex polygon has the measure of each interior angles to be less than 180^{o}.

But,

sum of interior angles of polygon = (n - 2) x 180^{o}

where n is the number of sides of the polygon.

For a convex 11-gon, we have;

sum of angles of a 11-gon = (11 - 2) x 180^{o}

                                         = 9 x 180^{o}

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Sum of angles of a 11-gon = 1620^{o}

To check: convex polygons' interior angles are less than 180^{o}.

so that,

each interior angle of 11-gon = \frac{1620}{11}

                                        = 147.273^{o}

3 0
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Mrrafil [7]

Answer:

25%

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7 0
3 years ago
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