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svlad2 [7]
2 years ago
5

Which pair of substances cannot form a buffered aqueous solution?

Chemistry
1 answer:
WARRIOR [948]2 years ago
5 0

HNO3 and NaNO3 cannot form a buffered aqueous solution from the following options.

A buffer solution (more precisely, pH buffer or hydrogen ion buffer) is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa. Its pH changes very little when a small amount of strong acid or base is added to it.

Buffer solutions are used as a means of keeping pH at a nearly constant value in a wide variety of chemical applications. In nature, there are many living systems that use buffering for pH regulation. For example, the bicarbonate buffering system is used to regulate the pH of bloodstream, and bicarbonate also acts as a buffer in the ocean.

Buffer solutions resist pH change because of a chemical equilibrium between the weak acid HA and its conjugate base A−:

HA ⇌ H⁺ + A⁻

Learn more about buffer solution here : brainly.com/question/8676275

#SPJ4

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one of the isotopes of sulfur is represented as sulfur -35 or S-35. what does the number 35 signify?
Temka [501]
35 is equal to it's mass number
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4 years ago
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What type of reaction is <br><br> Ammonia (NH3) breaking down into nitrogen gas and hydrogen gas
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Explanation:

Look at the reaction.

2NH3 ===> N2 + 3H2

It's a molecule that is breaking down to two elements on the periodic table. We used to call such a thing as a simple decomposition.

8 0
3 years ago
Find the number of atoms in 237g Cu (molar mass of Cu63.55g/mol)
MakcuM [25]
In order to find the amount of atoms you have to find the moles then multiply by Avogadro's Constant (L)

mol = \frac{MASS}{Molar Mass}
 
       = \frac{237 g}{63.55 g/mol}  &#10;
       
       =  3.73 mol

Number of atoms of Cu =  mol × L
                
                                      = 3.73 mol × (6.02 × 10²³)
                          
                                      = 2.245 × 10²⁴ atoms of copper


 
 


5 0
3 years ago
what is the empirical formula of vanadium 1 oxide given that 20.38 grams of vandium combines with oxygen to form 23.58 grams of
Alex

Answer:

The empirical formula is V₂O

Empirical formula of a compound is the formula that shows the simplest whole number ratio of the atoms of elements in a given compound. Empirical formula is normally calculated when the mass of each element in a compound is known or the percentage composition by mass of each element in a compound is known.

Step by Step Explanation:

Step 1: Percentage composition of each element

Percentage composition=(mass of an element/ mass of the compound)100%

Mass of Vanadium = 20.38 g

Mass of the compound = 23.58 g

% composition of Vanadium = (20.38 g/23.58 g) 100%

                                                 = 86.43 %

Mass of Oxygen = 23.58 g -20.38 g

                           = 3.2 g

% composition of oxygen = (3.2/g/23.58 g) 100%

                                          =  13.57%

Step 2: Find the number of atoms of each element in the compound

Number of atoms  = percentage composition/ atomic mass

Atomic mass of Vanadium = 50.94 g/mol

Number of atoms of V = 86.43 /50.94

                                  = 1.6967

Atomic mass of oxygen = 16 g/mol

Number of atoms of O = 13.57/16

                                      = 0.8481

Step 3:  Find the simplest ratio of atoms

Vanadium : Oxygen

            1.6967 : 0.8481

= 1.6967/0.8481 : 0.8481/0.8481

= 2: 1

Whole number ratio = 2 : 1

Therefore; the empirical formula is V₂O

8 0
3 years ago
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In which of these reactions is energy released​
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Answer:

What are the answers ?

Explanation:

6 0
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