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hichkok12 [17]
3 years ago
12

Determine the concentration of H+ in each solution at 25∘C

Chemistry
1 answer:
puteri [66]3 years ago
4 0

Answer:

1: [H+] = 0.01 M

2: [H+] = 0.0001 M

3: [H+] = 0.0001 M

Explanation:

Step 1: data given

pH = -log[H+]

pH = pOH = 14

Step 2:

1. A solution with pH = 2.0

pH = 2

-log[H+] = 2.0

[H+] = 10^-2

[H+] = 0.01 M

2. A solution with pH = 4.0

pH = 4

-log[H+] = 4.0

[H+] = 10^-4

[H+] = 0.0001 M

3. A solution with pOH = 10.0

pH = = 14 - 10 = 4

pH = 4

-log[H+] = 4.0

[H+] = 10^-4

[H+] = 0.0001 M

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5.00 g of an unknown compound was dissolved in 250.0 mL of water. The unknown compound was found to be a non-electrolyte and the
Zielflug [23.3K]

Answer:

This unknown compound has a molar mass of 33.74g/mole

Explanation:

<u>Step 1:</u> Given data

The formula for the osmotic pressure is:

π = MRT = 14.5 atm

⇒ with M = Concentration of the solution

⇒ with R = gas constant = 0.08206 L atm / mol K

⇒ with T = absolute temperature (in Kelvin) = 298K

<u>Step 2:</u> Calculate concentration

M = π/ RT

M = 14.5 / (0.08206 * 298)

M = 0.593 M this is 0.593 moles per L

<u>Step 3:</u> Calculate number of moles

Since the volume is only 0.250 L, the amount of moles is:

0.593 * 0.250 L = 0.1482 moles

<u>Step 4:</u> Calculate molar mass

The molar mass is : mass / moles

Molar mass of this unknown compund = 5g / 0.1482 moles = 33.74 g/mole

This unknown compound has a molar mass of 33.74g/ mole

4 0
3 years ago
How many carbon atoms are in each mole of calcium carbonate?
xeze [42]

Answer:

5 atoms are in each molecule of calcium carbonate

6 0
3 years ago
How many atoms are present in 0.529 moles of Li?
nirvana33 [79]

Answer:

<h2>3.18 × 10²³ atoms</h2>

Explanation:

The number of atoms can be found by using the formula

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From the question we have

N = 0.529 × 6.02 × 10²³

We have the final answer as

<h3>3.18 × 10²³ atoms</h3>

Hope this helps you

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3 years ago
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C) can give up electrons more readily than others.
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This created difference in charges, which create attraction 

hope this helps
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4 years ago
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