The focal length, like you said it's the distance between the FOCAL point and the mirror.
Hope this helps.... :)
Answer:39.8375
Explanation:
The mole for the equation is 1:1
Then the molar mass of KCl is 74.5g
Molar mass of k is 39
74.5g of KCl gives 39g of k
76.10g of KCl gives xg of k
X= 76.10×39/74.5
X= 2967.9/7
X= 39.8375
Answer:
PV=nRT where P=pressure in atm, V=volume is liters, n=numbber of moles, R=gas constant, 0.08206 L-atm/mole KL, and T=temperature in K (273 + C). So (5.67atm)(99.39L)=n(0.08206 L-atm/mol.K)(328.94K), solve for n, the number of moles, n=20.9 moles.
Explanation: