6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O
Explanation:
Given equation;
NaC₂H₃O₂ + Fe₂O₃ → Fe(C₂H₃O₂)₃ + Na₂O
To find the coefficient that will balance this we equation, let us set up simple mathematical algebraic expressions that we can readily solve.
Let us have at the back of our mind that, in every chemical reaction, the number of atom is usually conserved.
aNaC₂H₃O₂ + bFe₂O₃ → cFe(C₂H₃O₂)₃ + dNa₂O
a, b, c and d are the coefficients that will balance the equation.
conserving Na; a = 2d
C: 2a = 6c
H: 3a = 9c
O; 2a + 3b = 6c + d
Fe: 2b = c
let a = 1
solving:
2a = 6c
2(1) = 6c
c = 
2b = c
b = 
= 
d = 2a + 3b - 6c = 2(1 ) + (3 x ) - (6 x 
) = 
Now multiply through by 6
a = 6, b = 1, c = 2 and d = 3
6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O
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Balanced equation brainly.com/question/9325293
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There are 2 possible answers here : b and d.
The Ideal Gas Equation is : <u>PV = nRT</u>
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Here, when pressure is increased and temperature is lowered, the volume of the molecules will substantially decrease, which means it has deviated from ideal behavior.
Answer:
B. Green solution density is 1.06 g/ml and blue solution density is 1.20 g/ml
Explanation:
Density is given as,
D = Mass / Volume
Red Solution,
D = 25 g / 25 mL
D = 1 g/mL
Green Solution,
D = 26.5 g / 25 mL
D = 1.06 g/mL
Yellow Solution,
D = 28.2 g / 25 mL
D = 1.128 g/mL
Blue Solution,
D = 30 g / 25 mL
D = 1.20 g/mL
An occluded front forms when a warm air mass is caught between two cooler air masses.
Question is incomplete. Complete question is attached below
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Answer: Option A: HCO3-(aq.)
Reason:
From the reaction, it can be seen that following reaction occurs in forward direct
HCO3-(aq) + H2O(l) → H2CO3(aq) + OH-(aq)
In above forward reaction, HCO3- accepts proton from H2O to generate H2CO3. Thus, according to Lowry and Bronsted theory of acid-base,
HCO3- is a base, while
H2CO3 is a conjugate acid.
