In order to maintain neutrality, the negatively charged ions in the salt bridge will migrate into the anodic half-cell. A similar (but reversed) situation is found in the cathodic cell.
<h3>
What purpose does a salt bridge serve in an oxidation process?</h3>
Anions (negatively charged particles) are added to the solution of the oxidation half of the cell by the salt bridge, and cations (positively charged particles) are added to the solution of the reduction half of the reaction.
<h3>
What purpose does the salt bridge serve in a galvanic cell?</h3>
For instance, KCl, AgNO3, etc. In a galvanic cell, such as a voltaic cell or Daniel cell, salt bridges are typically used. A salt bridge's primary job is to assist in preserving the electrical neutrality of the internal circuit. Additionally, it aids in keeping the cell's response from reaching equilibrium.
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Answer:
a. Be and Mg
Explanation:
Be (beryllium) and Mg (magnesium) are both found in the alkaline earth metals family (group 2) on the periodic table. Elements in the same family or group have similar properties,
Ca and Br are in groups 2 and 17
Cl and Ar are in groups 17 and 18
Na and P are in groups 1 and 15
Answer:
2. Co(NO3)2 + H2
Explanation:
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In this case, we are evidencing a simple displacement reaction wherein the cobalt is able displace the hydrogen to produce cobalt (II) nitrate and gaseous hydrogen as a result of cobalt's higher activity:
Therefore, answer is 2. Co(NO3)2 + H2.
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The unit cell of Aluminum is a face-centered cubic structure. This lattice unit cell consists of 4 atoms per unit cell. The volume of the unit cell is a³ where a is the length of the side of the unit cell. In terms of radius r, volume is equal to:
V = (4r/√2)³
V = (4(0.143×10⁻⁹ m)/√2)³
V = 6.62×10⁻²⁹ m³
This is an exercise in<u> the General Combined Gas Law</u>.
To start solving this exercise, we obtain the following data:
<h3>
Data:</h3>
- V₁ = 4.00 l
- P₁ = 365 mmHg
- T₁ = 20 °C + 273 = 293 K
- V₂ = 2,80 l
- T₂ = 30 °C + 273 = 303 K
- P₂ = ¿?
We apply the following formula:
- P₁V₁T₂=P₂V₂T₁ ⇒ General formula
Where:
- P₁=Initial pressure
- V₁=Initial volume
- T₂=end temperature
- P₂=end pressure
- T₂=end temperature
- V₁=Initial temperature
We clear for final pressure (P2)
We substitute our data into the formula:
Answer: The new canister pressure is 539.224 mmHg.
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