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My name is Ann [436]
3 years ago
14

Janelle hikes along the beach every morning at the same time. Throughout the month, she notices the shoreline follows a pattern

of receding and advancing. What causes the shoreline to follow this pattern?
tides


water cycle


chemical weathering


erosion and deposition
Chemistry
2 answers:
avanturin [10]3 years ago
8 0

Answer:

Tides

Explanation:

just did it:)

Zina [86]3 years ago
7 0

Answer:

Erosion and deposition

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How many liters of oxygen gas (O2) are needed to produce 100 kJ of energy at STP? 2C6H6(I) + 1502(g) —> 12CO2(g)+6H2O(g)+3909
makkiz [27]

Answer: 8.59 L of oxygen gas are needed to produce 100 kJ of energy at STP

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atmosphere respectively.  

1 mole of every gas occupy volume at STP = 22.4 L

The balanced chemical reaction is:

2C_6H_6(I)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)

3909.9 kJ of of energy is produced by  = 15\times 22.4=336L

100 kJ of oxygen gas are needed to produce = \frac{336}{3909.9}\times 100=8.59L

7 0
3 years ago
Why do you think the Na+ ion is smaller than a neutral Na atom? Why do you think the Cl - ion is larger than a neutral Cl atom?
Sphinxa [80]

Answer:

Na+ ion is smaller than a neutral Na atom in the ion there was one more proton which will attract electron bring it closer to the center making the atomic radius smaller. Therefore making a Na+ ion is smaller than a neutral Na atom Explanation:

yes

7 0
3 years ago
How much heat in j is giving out when 85.0g of lead cools from 200.0 c to 10.0c
photoshop1234 [79]

Answer:

q = - 2067.2 J of Heat is giving out when 85.0g of lead cools from 200.0 c to 10.0 c.

Explanation:

The Specific Heat capacity of Lead is 0.128 \frac{J}{g\ ^{0}C}

This means, increase in temperature of 1 gm of lead by 1 ^{0}\ C will require 0.128 J of heat.

Formula Used :

q = m.c.\Delta T

q = amount of heat added / removed

m = mass of substance in grams = 85.0 g

c = specific heat of the substance = 0.128

q = m.c.\Delta T = Change in temperature

                                          = final temperature - Initial temperature

                                          = 10 - 200

                                          = -190 ^{0}\ C

put value in formula

q = -  85\times 0.128\times 190

On calculation,

q = - 2067.2 J

- sign indicates that the heat is released in the process

5 0
3 years ago
Which of the following characteristics do Element I and Element I have in common?
Nesterboy [21]

Answer:

Option C. The same number of energy levels.

Explanation:

From the diagram given above, element (i) belong to group 2 while element (ii) belong to group 6.

Also, both element i and ii belong to the same period (i.e period 4). This simply means that both element i and ii have the same number of energy levels.

NOTE: Elements in the same period have the same number of shells of electrons which simply means they have the same energy levels.

5 0
3 years ago
What is gold atomic number
Korolek [52]

Answer:

79

Explanation:

6 0
3 years ago
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