Answer:
Photosynthesis
Explanation:
Photosynthesis can be defined as the process whereby plants, some protistans, and some bacteria utilize the energy from sunlight to produce glucose from water and carbon dioxide. In early spring, there is the shift of plants from scanty winter branches to abundant spring leaves. When the leaves on the trees reduced in the fall, dead plants break down throughout the winter due to the activities of microbes. The microbes decompose the plant materials and generate carbon dioxide. This leads to increase in the level of carbon dioxide in the atmosphere. In the spring, leaves return to the plants/trees and the rate of photosynthesis increases greatly. This consumes more carbon dioxide and the level of carbon dioxide in the atmosphere reduced.
Which list of elements contains two metalloids?(1) Si, Ge, Po, Pb (3) Si, P, S, Cl(2) As, Bi, Br, Kr (4) Po, Sb, I, Xe
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The answer is (1). Si and Ge are both metalloids (semimetals)
Answer:
A/1. 10.9 mol O2
Explanation:
583 g x 1 mol SO3 x 3 mol O2 /
80.057 g mol SO3 x 2 mol SO3
- You just need to find molar mass of SO3, which is 80.057 g.
- Everything else came from formula. Further explanation...
- Always start with what they give, such as 583 g. Then find 1 mol of what is being produced, in this it is SO3. We already found this because we did molar mass above. Next. find how many moles of what they want, which is O2. Look in equation and you can see 3 mol in from of O2. Next, do the same for SO3 and you can find 3 mol in front of that. Lastly, just do the math.
- If you need a further explanation or more help on any problems I would be happy to help, just let me know.
Answer:
0.5ppm
Explanation:
Step 1:
Data obtained from the question.
Volume of water = 2500L
Mas of Cu = 1.25 g
Step 2:
Determination of the concentration of Cu in g/L. This is illustrated below:
Volume of water = 2500L
Mas of Cu = 1.25 g
Conc. of Cu In g/L =?
Conc. g/L = Mass /volume
Conc. of Cu in g/L = 1.25/2500
Conc. of Cu in g/L = 5x10^–4 g/L
Step 3:
Conversion of the concentration of Cu in g/L to ppm. This is illustrated below
Recall:
1g/L = 1000mg/L
Therefore, 5x10^–4 g/L = 5x10^–4 x 1000 = 0.5mg/L
Now, we know that 1mg/L is equal to 1ppm.
Therefore, 0.5mg/L is equivalent to 0.5ppm
