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2 years ago

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Energy in inductors: you need an inductor that will store 20 j of energy when a 3. 0-a current flows through it. what should be

its self-inductance?

1 answer:

Diano4ka-milaya [45]2 years ago

3 0

The self inductance can be calculated as 4.444 Henry.

The inductor will store energy = 20 joule,

current = 3 ampere.

<h3>What is Self inductance?</h3>

The current carrying conductor which allows or opposes the change of flow of current is known as self-inductance. The rate of change of current can also be given through self inductance.

Formula can be given for the energy in the inductor as,

E = 1 / 2 × L × I² joule.

where as, E - Energy

L - Inductance

I - Current flowing through the coil.

The equation can be rearranged as,

L = 2 E/ I²

= 2 × 20 / 3²

= 40 / 9

Hence, L = 4.4444 Henry

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A mass suspended from a spring bobs up and down one complete cycle every 2 s. its period is?

lilavasa [31]

The period is 2 seconds.

A period is a time taken to make one simple harmonic motion. It can be described as time divided by how many waves do. We can write the period formula as

T = t / n

where T is period, t is time and n is the amount of simple harmonic motions.

From the question above, we know that the mass travel up and down, it means that the cycle is one simple harmonic motion.

n = 1

t = 2s

Hence

T = t / n

T = 2 / 1

T = 2 second

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2 years ago

A certain electric dipole consists of charges q and –q separated by distance d, oriented along the x-axis as shown in the figure

Anna71 [15]

Electric field due to a point charge is given by formula

$E = \frac{kq}{r^2 + \frac{d^2}{4}}$

now due to negative charge also the magnitude of electric field will be same

only difference is the direction of field due to negative charge is radially inwards

now we can say that net field due to these two charges is given as

$E = 2E_0cos\theta$

$E = 2\frac{kq}{r^2 + \frac{d^2}{4}}*\frac{d/2}{\sqrt{r^2 + \frac{d^2}{4}}}$

$E = \frac{kqd}{(r^2 + \frac{d^2}{4})^1.5}$

now it is given that distance r is very large than "d" so we can say

$E = \frac{kqd}{r^3}$

<em>so above is the electric field due to dipole</em>

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3 years ago

A loudspeaker having a diaphragm that vibrates at 910 Hz is traveling at 75.0 m/s directly toward a pair of holes in a very larg

Alina [70]

To solve this problem we need to apply doppler equation,

Our values are:

$f_0 = 910Hz\\c = 75m\\v=344m/s\\\theta= 12.9\°\\$

Doppler equation is given by,

$f= \frac{v}{v-c} f_0$

Substituting,

$f= \frac{344}{344-75}*910$

$f = 1163Hz$

$\lambda = \frac{344}{1163}$

Wavelenght is equal to,

$\lambda = \frac{c}{f}$

$\lambda = 0.2956$

We can now find the distance by,

$d= \frac{1}{2}\frac{\lambda}{sin\theta}$

$d=\frac{1}{2}\frac{0.2956}{sin(12.9)}$

$d= 0.66m$

b) We can find at what angles would sound first cancel through the same equation of wavelenght,

$\lambda = \lambda{c}{f} = \frac{344}{1163}$

$d* sin\theta = \frac{1}{2}*\lambda$

$\theta = arcsin( 0.5*(344/1163)/0.66)=12.94\°$

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3 years ago

A sprinf has a potential energy of 84.08 J and a constant of 342.25 N/m. How far it been stretched? Use potential energy elastic

valina [46]

The spring has been stretched 0.701 m

Explanation:

The elastic potential energy of a spring is the potential energy stored in the spring due to its compression/stretching. It is calculated as

$E=\frac{1}{2}kx^2$

where

k is the spring constant

x is the elongation of the spring with respect to its equilibrium position

For the spring in this problem, we have:

E = 84.08 J (potential energy)

k = 342.25 N/m (spring constant)

Therefore, its elongation is:

$x=\sqrt{\frac{2E}{k}}=\sqrt{\frac{2(84.08)}{342.25}}=0.701 m$

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3 years ago

If a boulder has a mass of 50 kg and a potential energy of 490 j what is the height of the boulder

Mkey [24]

Potential energy = mass x g x height.
height = potential energy/mass x g
acceleration due to gravity on earth is 9.8 m/s
filling in your variables gives us:
490/50 x 9.8 = 1 meter

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4 years ago