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2 years ago

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Energy in inductors: you need an inductor that will store 20 j of energy when a 3. 0-a current flows through it. what should be

its self-inductance?

1 answer:

Diano4ka-milaya [45]2 years ago

3 0

The self inductance can be calculated as 4.444 Henry.

The inductor will store energy = 20 joule,

current = 3 ampere.

<h3>What is Self inductance?</h3>

The current carrying conductor which allows or opposes the change of flow of current is known as self-inductance. The rate of change of current can also be given through self inductance.

Formula can be given for the energy in the inductor as,

E = 1 / 2 × L × I² joule.

where as, E - Energy

L - Inductance

I - Current flowing through the coil.

The equation can be rearranged as,

L = 2 E/ I²

= 2 × 20 / 3²

= 40 / 9

Hence, L = 4.4444 Henry

Learn more about energy in inductors,

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$F_{AC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_1)^2}$

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