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saveliy_v [14]
3 years ago
13

Please help, which vector represent the force that will produce equilibrium with these two forces?

Physics
1 answer:
forsale [732]3 years ago
5 0

zzzzzzzzzzzzzzzzzzzzzz

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Plz help i really need this
ddd [48]

Answer:

The reactivity of metals increases as you move left in a period and as you move down in a group, so Marie needs to know the period and group of the element inside each box. Boxes that show locations in groups 1 or 2 or in period 8 contain the most reactive elements.

Explanation:

6 0
3 years ago
Read 2 more answers
?/1 Jorge traveled 5 miles north to school. He then traveled 3 miles west to the store. Then he left the store and traveled 5 mi
aleksklad [387]

Answer:

He's 3 miles west of school.

Explanation:

He went 5 miles up and 5 miles down which means that he really didn't go up or down.  In between that, he went 3 miles west so if the 5 milers don't count, this puts him at 3 miles west of school.

4 0
3 years ago
If a 12 kg cat is sitting 5 m up in a tree, how much PE does it have?
Helen [10]

Answer:

588 J

Explanation:

PE (potential energy) = (mass) x (gravity) x (height)

mass = 12 kg

gravity = 9.8m/s^2

height = 5 m

PE = (12) x (9.8) x (5) = 588 J (Joules)

5 0
3 years ago
A dock worker applies a constant horizontal force of 81.0 N to a block of ice on a smooth horizontal floor. The frictional force
AnnZ [28]

Answer:

The correct answer is:

(a) 84.240 kg

(b) 24.038 m

Explanation:

The given values are:

Force,

F = 81.0 N

Distance,

S = 13.0 m

Time,

t = 5.20 s

As we know,

The acceleration of mass will be:

⇒  a=\frac{2S}{t^2}

On substituting the given values, we get

⇒     =\frac{2\times 13.0}{(5.20)^2}

⇒     =\frac{26}{27.04}

⇒     =0.961538 \ m/s^2

(a)

The mass of the block will be:

⇒  m=\frac{F}{a}

On substituting the given values, we get

⇒       =\frac{81.0}{0.961538}

⇒       =84.240 \ kg

(b)

The final velocity after a given time i.e.,

t = 5.00 s

⇒  v=at

On substituting the values, we get

⇒     =0.961538\times 5.00

⇒     =4.8076 \ m/s

In time, t = 5.00 s

The distance moved by the block will be:

⇒  d=vt

On putting the values, we get

⇒     =4.8076\times 5.00

⇒     =24.038 \ m

5 0
3 years ago
N4M.6 A board has one end wedged under a rock having a mass of 380 kg and is supported by another rock that touches the bottom s
Hitman42 [59]

Answer:

it is safe to stand at the end of the table

Explanation:

For this exercise we use the rotational equilibrium condition

         Στ = 0

         W x₁ - w x₂ - w_table x₃ = 0

         M x₁ - m x₂ - m_table x₃ = 0

where the mass of the large rock is M = 380 kg and its distance to the pivot point x₁ = 850 cm = 0.85m

the mass of the man is 62 kg and the distance

            x₂ = 4.5 - 0.85

            x₂ = 3.65 m

the mass of the table (m_table = 22 kg) is at its geometric center

            x_{cm} = L/2 = 2.25 m

            x₃ = 2.25 -0.85

            x₃ = 1.4 m

let's look for the maximum mass of man

            m_{maximum} = \frac{ M x_1 -m_{table} x_3}{ x_2}

let's calculate

             m_{maximum} = \frac{ 380 \ 0.85 - 22 \ 1.4}{3.65}(380 0.85 - 22 1.4) / 3.65

             m_{maximum} = 80 kg

we can see that the maximum mass that the board supports without turning is greater than the mass of man

             m_{maximum}> m

consequently it is safe to stand at the end of the table

5 0
3 years ago
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