I think the answer is CuF2
Answer:
5.49×10⁻⁴ lbm
Explanation:
Convert volume to m³.
V = (200 cm³) (1 m / 100 cm)³ = 0.0002 m³
Find mass in kg.
m = ρV
m = (1.24507 kg/m³) (0.0002 m³)
m = 0.000249 kg
Convert mass to lbm.
m = (0.000249 kg) (2.205 lbm/kg)
m = 0.000549 lbm
m = 5.49×10⁻⁴ lbm
<span>protection from injustices</span>
Complete question:
If the swimmer could cross a 14 km channel maintaining the same average velocity as for the first 50 m in the pool, how long would it take?
For the first 50m in the pool, the average velocity was 2.08 m/s
Answer:
It would take for the swimmer approximately 1.87 hours.
Explanation:
If the swimmer maintains the average velocity on the channel, we should find and approximate value of the time it takes to cross the channel with the Galileo’s kinematic equation:
With x the displacement, v the average velocity and t the time, solving for t:
Answer:
1,1 m
Explanation:
Dado que;
coeficiente de fricción = 0,6
sabemos que W = R = mgcos 37 = 3.5Kg * 10m / s ^ 2 * cos37 = 27.95 N
coeficiente de fricción = fuerza / reacción normal (R)
Fuerza = 0.6 * 27.95 N
Fuerza (F) = 16.77 N
Recuerda que F = Ke
dónde;
K = constante de fuerza (15N / m)
e = extensión (lo desconocido)
e = F / K
e = 16,77 N / 15 N / m
e = 1,1 m