Answer:
Kinetic energy, E = 133.38 Joules
Explanation:
It is given that,
Mass of the model airplane, m = 3 kg
Velocity component, v₁ = 5 m/s (due east)
Velocity component, v₂ = 8 m/s (due north)
Let v is the resultant of velocity. It is given by :
![v=\sqrt{v_1^2+v_2^2}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bv_1%5E2%2Bv_2%5E2%7D)
![v=\sqrt{5^2+8^2}=9.43\ m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B5%5E2%2B8%5E2%7D%3D9.43%5C%20m%2Fs)
Let E is the kinetic energy of the plane. It is given by :
![E=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
![E=\dfrac{1}{2}\times 3\ kg\times (9.43\ m/s)^2](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%203%5C%20kg%5Ctimes%20%289.43%5C%20m%2Fs%29%5E2)
E = 133.38 Joules
So, the kinetic energy of the plane is 133.38 Joules. Hence, this is the required solution.
The answer is C (the same number of valence electrons)
Answer:
![t = 1.82](https://tex.z-dn.net/?f=t%20%3D%201.82)
Explanation:
Given
-- initial velocity
--- height
Required
Determine the time to hit the ground
This will be solved using the following motion equation.
![s = ut + \frac{1}{2}gt^2](https://tex.z-dn.net/?f=s%20%3D%20ut%20%2B%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
Where
![g = 9,8m/s^2](https://tex.z-dn.net/?f=g%20%3D%209%2C8m%2Fs%5E2)
So, we have:
![30.2 = 7.70t + \frac{1}{2} * 9.8 * t^2](https://tex.z-dn.net/?f=30.2%20%3D%207.70t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%2A%209.8%20%2A%20t%5E2)
![30.2 = 7.70t + 4.9 * t^2](https://tex.z-dn.net/?f=30.2%20%3D%207.70t%20%2B%204.9%20%2A%20t%5E2)
Subtract 30.2 from both sides
![30.2 -30.2 = 7.70t + 4.9 * t^2 - 30.2](https://tex.z-dn.net/?f=30.2%20-30.2%20%20%3D%207.70t%20%2B%204.9%20%2A%20t%5E2%20-%2030.2)
![0 = 7.70t + 4.9 * t^2 - 30.2](https://tex.z-dn.net/?f=0%20%20%3D%207.70t%20%2B%204.9%20%2A%20t%5E2%20-%2030.2)
![0 = 7.70t + 4.9t^2 - 30.2](https://tex.z-dn.net/?f=0%20%20%3D%207.70t%20%2B%204.9t%5E2%20-%2030.2)
![7.70t + 4.9t^2 - 30.2 = 0](https://tex.z-dn.net/?f=7.70t%20%2B%204.9t%5E2%20-%2030.2%20%20%3D%200)
![4.9t^2 + 7.70t - 30.2 = 0](https://tex.z-dn.net/?f=4.9t%5E2%20%2B%207.70t%20-%2030.2%20%20%3D%200)
Solve using quadratic formula:
![t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-b%5C%C2%B1%5Csqrt%7Bb%5E2%20-%204ac%7D%7D%7B2a%7D)
Where
![a = 4.9;\ b = 7.70;\ c = -30.2](https://tex.z-dn.net/?f=a%20%3D%204.9%3B%5C%20b%20%3D%207.70%3B%5C%20c%20%3D%20-30.2)
![t = \frac{-7.70\±\sqrt{7.70^2 - 4*4.9*-30.2}}{2*4.9}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7.70%5C%C2%B1%5Csqrt%7B7.70%5E2%20-%204%2A4.9%2A-30.2%7D%7D%7B2%2A4.9%7D)
![t = \frac{-7.70\±\sqrt{651.21}}{9.8}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7.70%5C%C2%B1%5Csqrt%7B651.21%7D%7D%7B9.8%7D)
![t = \frac{-7.70\±25.52}{9.8}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7.70%5C%C2%B125.52%7D%7B9.8%7D)
Split the expression
or ![t = \frac{-7.70-25.52}{9.8}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B-7.70-25.52%7D%7B9.8%7D)
or ![t = -\frac{33.22}{9.8}](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7B33.22%7D%7B9.8%7D)
Time can't be negative; So, we have:
![t = \frac{17.82}{9.8}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B17.82%7D%7B9.8%7D)
![t = 1.82](https://tex.z-dn.net/?f=t%20%3D%201.82)
Hence, the time to hit the ground is 1.82 seconds
A scientific journal article that is peer reviewed. This is because it is more likely not have factual information and sources to that information.
Answer:
b
Explanation:
it compresses hot air turning into cool air almost like a reverse tornado