Pls pls pls help meee plssss

Fofino [41]

Can u show us how the location looks please?

7 0

2 years ago

a paddle boat can move at a speed of 6km/h in still water. the boat is paddeled 16km downstream in a river in the same time it t

kaheart [24]

$v-the\ speed\ of\ the\ river\\\\16:(6+v)=8:(6-v)\\\\\frac{16}{6+v}=\frac{8}{6-v}\\-------------\\multiply\ on\ the\ cross\\-------------\\8(6+v)=16(6-v)\\\\48+8v=96-16v\\\\8v+16v=96-48\\\\24v=48\ \ \ /:24\\\\v=2\ (km/h)\leftarrow Answer$

5 0

3 years ago

A rectangular tank has length 4m, width 12m and height 3.5..i. If the tank is filled with water 2/3 of its capacity ,calculate t

ipn [44]

Answer:

The volume of the water in the tank is 112 m³

Step-by-step explanation:

The volume of the rectangular prism V = L × W × H, where

L is its length

W is its width

H is its height

∵ A rectangular tank has a length of 4 m, a width of 12 m, and

a height of 3.5 m

∴ L = 4 m

∴ W = 12 m

∴ H = 3.5 m

∵ V = L × W × H

∴ The volume of the tank = 4 × 12 × 3.5

∴ The volume of the tank = 168 m³

∵ The tank is filled with water $\frac{2}{3}$ of its capacity

→ That means the volume of the water is $\frac{2}{3}$ the volume of the tank

∵ The volume of the water = $\frac{2}{3}$ the volume of the tank

∴ The volume of the water = $\frac{2}{3}$ × 168

∴ The volume of the water = 112 m³

∴ The volume of the water in the tank is 112 m³

3 0

2 years ago

Ln how many ways 5 person sitted in a round table having 8 seats?

kvasek [131]

Answer: First consider the case that ‘just’ 5 persons are seated around a round table.

Clearly, ‘just’ 5 persons can be seated around a round table in (5 - 1)! = 4! = 24 ways.

Now, one vacant chair is to be inserted among them.

Say, for a particular sitting arrangement ‘ABCDE’; there are 5 scopes available for inserting the vacant chair - between A and B, between B and C, between C and D, between D and E & between E and A.

So, there are 5*24 = 120 ways available that 5 persons can sit around a round table with 6 chairs.

Step-by-step explanation:

First consider the case that ‘just’ 5 persons are seated around a round table.

Clearly, ‘just’ 5 persons can be seated around a round table in (5 - 1)! = 4! = 24 ways.

Now, one vacant chair is to be inserted among them.

Say, for a particular sitting arrangement ‘ABCDE’; there are 5 scopes available for inserting the vacant chair - between A and B, between B and C, between C and D, between D and E & between E and A.

So, there are 5*24 = 120 ways available that 5 persons can sit around a round table with 6 chairs.

5 0

3 years ago

Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (

Fudgin [204]

A.

$\displaystyle\frac1a-\frac1h=\frac1h-\frac1b$
$\implies\displaystyle\frac{h-a}{ah}=\frac{b-h}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac{ah}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac ab$

b.

$\displaystyle h=\frac{2ab}{a+b}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{a(b-a)}{b(b-a)}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac ab$

The other direction can be proved by following the manipulations in the reverse order.

7 0

2 years ago