Really need help with Dilations in the Coordinate Plane

Mathematics

1 answer:

zimovet [89]1 year ago

4 0

Answer:

I'd say (x,y) --> (2x,2y)

Step-by-step explanation:

Please understand if I'm wrong because I couldn't enhance the image. The quality made it a bit hard for me to accurately tell.

Sorry if I'm wrong.

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If C is the incenter of ∆AMD, m∠A M C = 3 x + 6 and m∠ DMC= 8 x − 49.

Sunny_sXe [5.5K]

<h2>Answer:</h2><h2>51.</h2>

Hope this will help you lot.

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My final balance after 48 months was $896.00. if i bring back originally put$800.00 into the bank, what was the interest rate?

fomenos

The interest rate is $96.00.

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2 years ago

HELPPP

Mazyrski [523]

Answer:

Hello,

Step-by-step explanation:

y-intercept: x=0 ,f(0)=-10

$x^3-8x^2+17x-10\\\\=x^3-5x^2-3x^2+15x+2x-10\\\\=x^2(x-5)-3x(x-5)+2(x-5)\\\\=(x-5)(x^2-3x+2)\\\\=(x-5)(x^2-x-2x+2)\\\\=(x-5)(x(x-1)-2(x-1))\\\\=(x-5)(x-1)(x-2)\\$

x-intercepts are: 5,1,2.

6 0

2 years ago

Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a

cluponka [151]

Answer:

B. Train B

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

$\text{Distance}=\text{Speed*Time}$

$\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}$

$\text{Distance traveled by train A}=90\times 3{\text{ miles}$

$\text{Distance traveled by train A}=270{\text{ miles}$

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

$\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}$