<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
∠1 and ∠8 are alternate exterior angles and ∠3 and ∠6 are alternate interior angles
step-by-step explanation:
When the transversal crosses line m and n, alternate angles are the pair of angles formed on the outside of each of the lines and opposite side of the transversal (∠1 and ∠8). However,alternate interior angles will form opposite of the transversal but inside the lines.(∠3 and ∠6 ).
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brainly.com/question/12441758
Keywords : Transversal, angles
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Answer:
456
Step-by-step explanation:
Let X be the SATscore scored by the students
Given that X is normal (1000,200)
By converting into standard normal variate we can say that
is N(0,1)
To find the top 10% we consider the 90th percentile for z score
Z 90th percentile = 1.28
i.e. only students who scored 456 or above only should be considered.
