How do I find the equation of the axis of symmetry and the coordinates of the vertex?

1 answer:

5 0

For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry is a vertical line x=−b2a . Example 1: Find the axis of symmetry of the parabola shown. The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola.

You might be interested in

Obi's age is twice oba's age 4 years ago obi was three times as old as oba. find their ages

frutty [35]

Answer:

Obi's age is 18 and Oba's age is 9

Step-by-step explanation:

Let Obi's age be x and Oba's age be y

Condition 1:

x = 2y -----------(1)

Condition 2:

(x-4) = 3(y-4)

=> x -4 = 3y-12

=> x - 3y = -9 -----(2)

Putting eq (1) in (2)

2y - 3y = -9

=> -y = -9

=> y = 9

Now,

x = 2y

=> x = 2(9)

=> x= 18

8 0

3 years ago

Read 2 more answers

Determine the equation of the parabola shown in the diagram in factored form. (check picture below)

krok68 [10]

Answer:

$(x+1)(x-3)$

Step-by-step explanation:

A quadratic in factored form is usually expressed as: $a(x\pm a)(x \pm b)$ where the sign of a and b depends on the sign of the zero. And I said "usually" since sometimes the x will have a coefficient. Anyways in the quadratic there are two zeroes at x=-1 and x=3. This can be written as: $a(x+1)(x-3)$ . Notice how the signs are different? This is because when you plug in -1 as x you get a factor of (-1+1) which becomes 0 and it makes the entire thing zero since when you multiply by 0, you get 0. Same thing for the x-3 if you plug in x=3. Now a is in front and it can influence the stretch/compression. To find the value of a, you can take any point (except for the zeroes, because it will make the entire thing zero, and you can technically input anything in as a)