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2 years ago

Solve the inequality |3x+4|>6

Mathematics

2 answers:

professor190 [17]2 years ago

8 0

Answer:

$\left(- \infty, -\dfrac{10}{3}\right) \cup \left(\dfrac{2}{3}, \infty\right)$

Step-by-step explanation:

To solve an inequality containing an absolute value:

Isolate the absolute value on one side of the equation.
Apply the relevant absolute rule.
Solve both cases.

Given inequality:

$|3x+4| > 6$

Apply the absolute rule:

$\textsf{If }\:|u| > a,\:a > 0\:\textsf{ then }\:u < -a \:\textsf{ or }\: u > a$

Therefore:

$\begin{aligned}\text{\underline{Case 1}} && \text{\underline{Case 2}}\\3x+4 & < -6 \quad & 3x+4 & > 6\\3x & < -10 \quad & 3x & > 2\\x & < -\dfrac{10}{3} \quad & x & > \dfrac{2}{3}\end{aligned}$

So the solution to the inequality in interval notation is:

$\left(- \infty, -\dfrac{10}{3}\right) \cup \left(\dfrac{2}{3}, \infty\right)$

Murljashka [212]2 years ago

3 0

Answer:

x > 2/3 or x < -10/3

Step-by-step explanation:

|3x + 4| > 6

To solve an absolute value inequality of the form |X| > b, where X is an expression, and b is a number, change the inequality into this compound inequality:

X > b or X < -b

Here, X is 3x + 4.

b is 6.

We get the compound inequality:

3x + 4 > 6 or 3x + 4 < -6

3x > 2 or 3x + 4 < -6

x > 2/3 or 3x < -10

x > 2/3 or x < -10/3

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