Supplementary angles , when added, = 180
complimentary angles, when added, = 90
< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary
< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143
< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26
< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97
cant read all of the last one.....but if they are complimentary, and
< U = 41, then the other angle is : (90 - 41) = 49
Answer:
Tara is 27 and Adam is 31.
Step-by-step explanation:
Tara: x years old
Adam: x+4
Subtract the five years to get their current age
x-5 and x+4-5
x-5 and x-1
(x-5) + (x-1) = 48
x-5 + x-1 = 48
2x - 6 = 48
2x= 48+6
2x= 54
x= 27
Tara is 27 and Adam is 31
1)
∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰
AB = 370 m
AC = 510 m
To find BC we can use cosine law.
a² = b² + c² -2bc*cos A
|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)
|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =
|BC| ≈ 553 m
2)
To find ∠ACB, we are going to use law of sine.
sin(∠BAC)/|BC| = sin(∠ACB)/|AB|
sin(76⁰)/553 m = sin(∠ACB)/370 m
sin(∠ACB)=(370*sin(76⁰))/553 =0.6492
∠ACB = 40.48⁰≈ 40⁰
3)
∠BAC = 76⁰
∠ACB = 40⁰
∠CBA = 180-(76+40) = 64⁰
Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰
4)
Shortest distance from A to BC is height (h) from A to BC.
We know that area of the triangle
A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).
Also, area the same triangle
A= (1/2)|BC|*h = (1/2)*553*h.
So, we can write
(1/2)*370*510*sin(76⁰) =(1/2)*553*h
370*510*sin(76⁰) =553*h
h= 370*510*sin(76⁰) / 553= 331 m
h=331 m
I would approach the problem like this:
1 oz bottle.............................30cm^3
33 oz bottle.............................xcm^3
in a 33 oz bottle will be x=33*30=990cm^3
density=mm/v
13.6g/cm^3= m/ 990cm^3
m= 13.6 * 990=13464 g
or 13.464 kg in a 33 oz bottle
Answer:
**If the interest is by year then this should work
The interest is $15600 and the amount is $80600.
Step-by-step explanation:
Problem
You deposit $65000 into a bank account paying 6% simple interest per year. You left the money in for 4 years. Find the interest earned and the amount at the end of those 4 years?
Result:
The interest is $15600 and the amount is $80600.
