Draw the 2 resonance structures of Malachite Green, and indicate which one is the equivalent contributor, and which one is the m
1 answer:
The two structures at the right of the image are the greatest contributors to the resonance structure of malachite green.
<h3>What is resonance structure?</h3>In some cases, one single structure is insufficient to explain the properties of a substance. Now, we know that in such cases we have to invoke more than one structure in order to efficiently discuss the chemistry of the compounds in question.
In this case, we can see from the image that the three structures of malachite green are all resonance structures. However, the two structures at the right hand side are the greatest contributors because they are more conjugated. Hence, the two structures at the right of the image are the greatest contributors to the resonance structure of malachite green.
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Answer : The value of equilibrium constant for this reaction at 328.0 K is
Explanation :
As we know that,
where,
= standard Gibbs free energy = ?
= standard enthalpy = 151.2 kJ = 151200 J
= standard entropy = 169.4 J/K
T = temperature of reaction = 328.0 K
Now put all the given values in the above formula, we get:
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = 95636.8 J
R = gas constant = 8.314 J/K.mol
T = temperature = 328.0 K
K = equilibrium constant = ?
Now put all the given values in the above formula, we get:
Therefore, the value of equilibrium constant for this reaction at 328.0 K is