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Rainbow [258]
2 years ago
6

Draw the 2 resonance structures of Malachite Green, and indicate which one is the equivalent contributor, and which one is the m

inor contributor.
Chemistry
1 answer:
Yuri [45]2 years ago
7 0

The two structures at the right of the image are the greatest contributors to the resonance structure of malachite green.

<h3>What is resonance structure?</h3>

In some cases, one single structure is insufficient to explain the properties of a substance. Now, we know that in such cases we have to invoke more than one structure in order to efficiently discuss the chemistry of the compounds in question.

In this case, we can see from the image that the three structures of malachite green are all resonance structures. However, the two structures at the right hand side are the greatest contributors because they are more conjugated. Hence, the two structures at the right of the image are the greatest contributors to the resonance structure of malachite green.

Learn more about resonance structure:brainly.com/question/23287285

#SPJ1

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describe in general terms an experiment to determine the molal freezing point depression constant kf of water. Assume the availa
Dvinal [7]
A solution (in this experiment solution of NaNO₃) freezes at a lower temperature than does the pure solvent (deionized water). The higher the solute concentration (sodium nitrate), freezing point depression of the solution will be greater.
Equation describing the change in freezing point: 
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b -  molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
First measure freezing point of pure solvent (deionized water). Than make solutions of NaNO₃ with different molality and measure separately their freezing points. Use equation to calculate Kf.

6 0
3 years ago
Estimate the heat of neutralization of H3PO4 in kJ/mol given these data: Heat transferred = 2.5 x 102 J Moles of H3PO4 = 1.4 x 1
OlgaM077 [116]
Below are the steps to get the answers:

<span>1.) write out the balance equation 3NaOh+H3PO4->Na3PO4+3H2O
 
2.) You are given everything needed to calculate q=heat transfer=2.2*10^2, H3PO4 moles= 1.5*10^-3, NaOH moles=5.0*10^-3
 
3.) equation is deltaHneutraliztion=q/Moles of limiting reagent H3PO4 is limiting reagent because lowest moles, and is used up first
 
4.) Now plug in variables DeltaH=2.2*10^2(1.5*10^3)= 146.67kj/mole Notice we had to convert J to kj, </span>
7 0
3 years ago
Which atoms make up a molecule of sodium bicarbonate.
Ratling [72]

Answer:

Its chemical formula is NaHCO3. Its formula consists of one sodium (Na) atom, one hydrogen (H) atom, one carbon (C) atom and three oxygen (O) atoms.

Explanation:

Hope this helps

8 0
2 years ago
What is the ph of a solution that contains 1.0 l of 0.10 m ch3cooh and 0.080 m nach3coo after 0.03 moles of naoh added?
zimovet [89]

Answer: pH = 4.996

Explanation:

No of moles = molarity x volume

:• no of moles of CH3COOH = 0.1M x 0.1L

n(CH3COOH) = 0.1mol

Since 0.03mole of NaOH is added, then 0.03 mole of CH3COOH will be converted to the conjugate.

Therefore, Moles of CH3COOH becomes,

0.1 - 0.03 = 0.07 mol

Subsequently, the moles of CH3COONa increases and becomes,

0.08 + 0.03 = 0.11 mol

Using the Hendersom-Hasselbach equation,

pH = pKa + log [Moles of conjugate÷ moles of Ch3COOH]

From literature, pKa of Ch3COOH is 4.8

Thus,

pH = 4.8 + log [0.11/0.07]

pH = 4.8 + 0.1963

pH = 4.996

4 0
3 years ago
If you have 25.0 ml of a 6.50m naoh solution and you add 10.0 ml of water to it, what is the new concentration?
uranmaximum [27]
36.5ml is the new concentration so, its a chemical change if there's something new
5 0
3 years ago
Read 2 more answers
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