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Rainbow [258]
1 year ago
6

Draw the 2 resonance structures of Malachite Green, and indicate which one is the equivalent contributor, and which one is the m

inor contributor.
Chemistry
1 answer:
Yuri [45]1 year ago
7 0

The two structures at the right of the image are the greatest contributors to the resonance structure of malachite green.

<h3>What is resonance structure?</h3>

In some cases, one single structure is insufficient to explain the properties of a substance. Now, we know that in such cases we have to invoke more than one structure in order to efficiently discuss the chemistry of the compounds in question.

In this case, we can see from the image that the three structures of malachite green are all resonance structures. However, the two structures at the right hand side are the greatest contributors because they are more conjugated. Hence, the two structures at the right of the image are the greatest contributors to the resonance structure of malachite green.

Learn more about resonance structure:brainly.com/question/23287285

#SPJ1

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What is the purpose of attaching the clip/ clamp with graphite of the the pencil to the battery?
Sonja [21]
The pencil attached to the negative terminal of the battery collects hydrogen gas while the one connected to the positive terminal collects oxygen.
4 0
3 years ago
The standard free-energy changes for the reactions below are given. Phosphocreatine → creatine + Pi ∆ G'° = –43.0 kJ/mol ATP → A
Jet001 [13]

Answer:

-12.5 kJ/mol

Explanation:

The free-energy predicts if a reaction is spontaneous or not. If it is, ΔG < 0. When a reaction happens by steps, the free-energy of the global reaction can be calculated by the sum of the free-energy of the steps (Hess law). If it's needed to operations at the reaction the same operation must be done in the value of ΔG (if the reaction is inverted, the signal of ΔG must be inverted).

Phosphocreatine → creatine + Pi ∆G'° = –43.0 kJ/mol

ATP → ADP + Pi                             ∆G'° = –30.5 kJ/mol (x-1)

--------------------------------------------------------------------------------------

Phosphocreatine → creatine + Pi ∆G'° = –43.0 kJ/mol

Pi + ADP → ATP                             ∆G'° = 30.5 kJ/mol

The bold compounds are in opposite sides, so they'll be canceled in the sum of the reactions:

Phosphocreatine + ADP → creatine + ATP

∆G'° = -43.0 + 30.5

∆G'° = -12.5 kJ/mol

5 0
2 years ago
Molar mass of c16h19n305s
Masja [62]

Answer:

365.212

Explanation:

According to the given situation, the calculation of molar mass is shown below:-

Data provided

c_{16}\ h_{19}\ n_3\ o_5\ S

Molar mass = 16 × 12 + 19 × 1.008 + 3 × 14 + 5 × 16 + 32.06

= 192 + 19.152 + 42 + 80 + 32.06

Molar mass = 365.212

Therefore for determining the molar mass we simply solve the above equation.

So, the correct answer is 365.212

5 0
3 years ago
Now we add 0.15 mol of naoh to 1.00 liter of the solution that was given in part 1. what is the ph of the solution after the nao
AnnyKZ [126]
Hello there.

<span>Now we add 0.15 mol of naoh to 1.00 liter of the solution that was given in part 1. what is the ph of the solution after the naoh addition? answer in units of ph.

</span><span>not sodium nitrate</span>
8 0
3 years ago
How many moles of potassium nitrate are required to make 550 mL of a 2.1M solution?
stira [4]

Answer:

1.155 moles of potassium nitrate are required to make 550 mL of a 2.1M solution.

Explanation:

In a mixture, the chemical present in the greatest amount is called a solvent, while the other components are called solutes.

Molarity is a unit of concentration of a solution and indicates the amount of moles of solute that appear dissolved in each liter of the mixture. In other words, the Molarity (M) or Molar Concentration is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

Molatity( M)=\frac{number of moles of solute}{Volume}

Molarity is expressed in units (\frac{moles}{liter}).

In this case:

  • Molarity= 2.1 M
  • number of moles of solute= ?
  • Volume= 550 mL= 0.550 L (being 1L=1000 mL)

Replacing:

2.1 M= 2.1 \frac{moles}{liter} =\frac{number of moles of solute}{0.550 liters}

Solving:

number of moles of solute= 2.1 M* 0.550 L

number of moles of solute= 1.155 moles

1.155 moles of potassium nitrate are required to make 550 mL of a 2.1M solution.

4 0
3 years ago
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