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Anastaziya [24]
3 years ago
12

An unknown compound has the following chemical formula: NO_x

Chemistry
1 answer:
vodomira [7]3 years ago
3 0

Answer:

NO_x

Explanation:

you said it

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The value for Kw is 1.0 x 10-14 at 298K, but this value is temperature dependent. Given what you know about Kw and acid/base che
ankoles [38]

Answer:

6.92; neutral

Explanation:

Kw = [H^+][OH^-] = 1.47 × 10^-14

pKw = pH + pOH = 13.83

At neutrality, [H^+] = [OH^-] and pH = pOH

2pH = 13.83

 pH =  6.92

The pH will be 6.92.

At 303 K, this will be the neutral pH, because [H^+] = [OH^-]

8 0
4 years ago
An aqueous solution is 1.00% by mass ethanol, CH3CH2OH, and has a density of 0.996 g/mL.
Katarina [22]

The molarity of ethanol in the solution is 0.217 M

<h3>Further explanation</h3>

Given

1% by mass

density = 0.996 g/ml

Required

The molarity

Solution

mass/ml of Ethanol :

1% x 0.996 g/ml = 0.00996 g/ml

For 1 L solution :

0.00996 g/ml x 1000 ml/L = 9.96 g/L

Convert to mol/L(MW ethanol=46 g/mol) :

9.96 g/L : 46 g/mol= 0.217 mol/L = 0.217 M

Or you can use equation :

\tt M=\dfrac{\%mass\times \rho\times 10}{MW}\\\\M=\dfrac{1\times 0.996\times 10}{46}=0.217

3 0
3 years ago
Oxygen gas generated in the thermal decomposition of potassium chlorate is collected over water. At 24ºC and an atmospheric pres
Yanka [14]

Answer:

its 0.163 g

Explanation:

From the total pressure and the vapour pressure of water we can calculate the partial pressure of O2​

PO 2 =P t −P H 2 O

​= 760 − 22.4

=  737.6 mmHg

From the ideal gas equation we write.

W= RT/PVM = (0.0821Latm/Kmol)(273+24)K(0.974atm)(0.128L)(32.0g/mol/) =0.163g

6 0
3 years ago
Given: N2 + 3Cl2 → 2NCl3, ΔH = 464 kJ/mol Use the given bond energies and the periodic table to calculate the energy change in t
guapka [62]

The given chemical reaction is:

N_{2}+3Cl_{2}-->2NCl_{3}

ΔH^{0}_{reaction}=∑BE(reactants)-∑BE(products)

                 = {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]

                     = 467 kJ/mol

Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:

Moles of chlorine = 85.3 g Cl_{2}* \frac{1 mol Cl_{2}} {70.91 g Cl_{2}  }

                             = 1.20 mol Cl_{2}

Heat change when 1.20 mol chlorine reacts

                             = 1.20 mol * \frac{467kJ}{mol} =560.4 kJ

6 0
3 years ago
Can someone please answer this for me
geniusboy [140]

Answer:

phone, microwave, internet box

5 0
3 years ago
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