Answer:
6.92; neutral
Explanation:
Kw = [H^+][OH^-] = 1.47 × 10^-14
pKw = pH + pOH = 13.83
At neutrality, [H^+] = [OH^-] and pH = pOH
2pH = 13.83
pH = 6.92
The pH will be 6.92.
At 303 K, this will be the neutral pH, because [H^+] = [OH^-]
The molarity of ethanol in the solution is 0.217 M
<h3>Further explanation</h3>
Given
1% by mass
density = 0.996 g/ml
Required
The molarity
Solution
mass/ml of Ethanol :
1% x 0.996 g/ml = 0.00996 g/ml
For 1 L solution :
0.00996 g/ml x 1000 ml/L = 9.96 g/L
Convert to mol/L(MW ethanol=46 g/mol) :
9.96 g/L : 46 g/mol= 0.217 mol/L = 0.217 M
Or you can use equation :

Answer:
its 0.163 g
Explanation:
From the total pressure and the vapour pressure of water we can calculate the partial pressure of O2
PO 2 =P t −P H 2 O
= 760 − 22.4
= 737.6 mmHg
From the ideal gas equation we write.
W= RT/PVM = (0.0821Latm/Kmol)(273+24)K(0.974atm)(0.128L)(32.0g/mol/) =0.163g
The given chemical reaction is:

Δ
∑BE(reactants)-∑BE(products)
= {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]
= 467 kJ/mol
Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:
Moles of chlorine = 
= 1.20 mol 
Heat change when 1.20 mol chlorine reacts
= 
Answer:
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